sree DEBASISH DASGUPTA: SUPPORTING CLUE for E = F/s

F = Es or E = F/s or s = F/E.

Sree DEBASISH DASGUPTA

* SUPPORTING CLUE for E = F/s *

We know one proton is 1837 time heavier than electron, and one neutron mass value equal energy = 938 MeV.

So 939/1837= 0.511 unit energy equal of one mass of electron.(And angel 11.25 / 22 = 0.51113 ).

When collusion with one “L” that moment – 0.511 x 0.413334 = 0.2112796 add one time and space 0.2112796 + 1.296 = 1.5072796 unit energy. As per my opinion E = m – (m/10).

Mass = ( ex10) / 9 = (1.50728 x10) / 9 = 15.0728 / 9 = 1.674755 unit mass.

And again 1.5072796 x 9 = 13.56 unit energy ( as per Scientist ‘Bhore’ I have several time write about that in my article in short “ASOLSD” see also picture 6)

1837 X 5.334 (Force) = 9798.588.Root = (i) 98.98766 Root = (ii) 9.94925 Root = (iii) 3.15424 Root = (iv) 1.776 Root = (v) 1.332

..(i) nearer 100 (ii) nearer 10,(iii) nearer ‘Pi’. Or ‘h’ bar (iv) mass (v) 4/3, (as per my opinion see about digit “10” )

1837 x 1.602 (energy) = 2942.874 Thirty two(32, max electron in one orbit) Root = 1.283509 x 7 = 8.98456 (C² as per my calculation)

1837 x 1.296 (Time & Space) = 2380.75 Twenty seven (3x3x3=27) Root = 1.3337=(4/3) for details read my all article at Facebook, Twitter, Blog’s By google search.A Story Of Latest Scientific Discovery.

Now ---1837 x 1.11* (see latter) = 1935 Sixteen Root = 1.6047 (energy), Square = 2.5754 Square = 6.63273 (Planck Constant) Square = 43.98 =14 x Pi ,(See About 42/3=14 , in my article)

*** That means 1839 times ,Force, energy, time etc. present in a neutron.***

[ So Total Force x energy x time & space = 9798.588 x 2942.874 x 2380.75 = 68651330478.747, 68651330478.747 nine Root (9) = 16, [ SEE Picture No 9,& 9A]

And when add total time 1935 , 68651330478.747 x 1935= 1328 4032 4476375.445, if we Root it step by step after 7^th step we will get see 1.289254, 1.289254 x 7 = “9”, ( or Root 128, For Why 128 ?, 0.53 x 100 = 53, & 53 / *0.413334* = 128. & 3 x 3 =”9” , 3 x 3 x 3 = 27) and if 1328 4032 4476375.445 twenty seven (27, 3x3x3 = 27) Root = 3.33, (Displacement) Next … several time I write about 1.289254 in my article ASOLSD.

So that means : (1328 4032 4476375.445 / 1.289254 ) = 103036581213923.28043969613435366 times 1.289254 is present in a neutron .

Let us see : - step by step Root to 103036581213923.28043969613435366 ,after sixth (6^th) step (or 64 Root over) we will get result 1.65559 ,we know one neutron 1839 times heavier than one electron, 1839 x 9 = 16551 divided by 10,000 = 1.6551 it same uint.And after 7^th step (or 128 Root over) get resut 1.2866976140160393105164440327068 x 7 = “9”

Again if Nine Root 103036581213923.28 get result 36, (36 x 10 = 360 degree angle 36 x 100 = 3600 sec. Time.) AND (27) twenty seven ROOT GET 3.3, For clear understand see picture 9 & 9A ]

*1.11 to the power 32** = 28.2056 Root (as per a² +b²=c²= 28.17 & 5.31 is10 times of ‘H’ atoms 1^st orbit radius, 0.53, or as per my opinion force OR Force for revolving electron around the orbit)

As per formula c = Root over (a² + b² + 2ab) = Root over (a + b)² = a + b

..a + b = (4.13334 + 3.33) = 7.46334, Root 7.46334 = 2.73191 Root = 1.653 Root = 1.285632.

1.285632 x 7 = 8.999 or “9”. (4L= 0.413334x4=1.653336)

Please see details of ‘7.46334’at “A Story Of Latest Scientific Discovery”, IOSRPHR Journal Vol-8,Issue-5,Version-1 Page No.28, OR Social Media by *GOOGLE* search.

As per my view *1.11 is Time need for create Displacement to Acceleration. In the time of revolving electron around the orbit. So Time = Root 1.11=1.05365 unit.

We know Force = mass x f (Acceleration) = mass x (changing motion / Time) = Momentum/Time, ie changing of Momentum = Force x Time.

So factor of time & mass, as per my view E= F/s or s = F/E. or F = Es [Force=5.334, Energy = 1.602, Displacement (s) = 3.33, Time = 1.05365,Time square= 1.11 ]

Here Acceleration = (3.33 /1.11) = 3 unit.

So as per law F = ma, m=F/a or mass=5.334/3= 1.778 unit. [When Time is 1.11]

We know As per law P=mf or P = mass x (v – u) / time,[Here v= end & u= starting motion, ]

P = 1.782662 mass x (3.33 – 3 = 0.33) / 1.11 = 0.58828 / 1.11 or 0.53 it is radius of “H” atom’s 1^st orbit. And this total calculation makes from 0.53…unit.

NOW – see also –

(a) 1/3 = 0.33…,

(b) 5.334 / 1.05356 = 5.06283458 , 5.06283458 four Root = 1.5 it is ½ of 3, (some time we use ½ spin ext.)

(d) 3.33 / 0.413334 = 8.056321, 8.056321 eight Root = 1.297 all most 1.296 (Time & Place)

(e) 5.3 + 1.2919 (constant of Visible Light) = 6.5919, 6.5919 sixteen Root = 1.125 x 10 =11.25 angle. [ already explain about 11.25 & 1.125 in my article ]

(f) 5.334 + 1.2919 = 6.625 Planck constant. Root = 1.6044 unit energy, [Please see COSMOSGONY 1&2, and “E = m – (m/10)” articles ]

## (g) 32** Root = 5.6568, Root = 2.378, Root 1.54221,Root 1.1241,Root = 1.11, Root= 1.055 It is time for produce an atom from Neutron. Four Root 1.24eV= 1.055.,Force= 5.334, Root sixteen 5.334 = 1.11.

[except 32 All are already explain in COSMOGONY & others article SEE also E = F/S, ‘Pic 9’ ]

[ Establish My all opinion & all formula and also L= 0.413334,all most TRUE]

For details please see my all articles, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH.

[ No Part of ALL this publication may be reproduce or any form or any means or any information without permission from the author or chip in charge :by:- M.N.G.R.W.S ]

sree DEBASISH DASGUPTA

রবিবার, ১৭ জুন, ২০১৮

SUPPORTING CLUE for E = F/s

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