সোমবার, ৩০ ডিসেম্বর, ২০১৯

Atomic Mass Energy and Constant


                                                                            Preface
   
   In childhood, during study different types of foolish question come in mind like if the unit of the respected scientists ‘Einstein’ equation, e=mc^2 the unit of  ‘e’ is changed then, ‘m’ also will be changed . Now if c^2 unit is changed then, why the mass, energy will not be changed? Who is the exponent of element? Why iron should not be changed into copper? Why nature is the exponent of all those powers. To get answer the search is complete, when it is seem 0.413324 digits, on its base all those essays are written
In the present essay, the given information, in that, all those used units like – joule, calorie, eV, different energy’s unit which is recognised by renowned scientists, those units are energy within that matter  (surely, mass of that object) by comparing it is deduced . Example – 1 Kg sugar,= 3870,calorie energy, or 1 litter petrol = 60 km travel range in a 100 c.c engine, or a xx Horse Power, Generator 2 hours...;                            Now if we take c.c , hour, Hp , calorie;  Kg , obviously is associated with any relation . But if we calculate this energy in different unit then, it will take difficult and large shape.
Now , the main aim is to solve energy with different energy or , the relation of matter with different energy the relationship is very secondary but to solve the problem Is the primary motive but we know those unit is practically set up by calculating math’s problem, those digits will be unchanged , like – 3 Apples = 5 mangoes. Now, if it is the relation between apples and mangoes size, content, weight, mass etc. will be unchanged then, we will take it as the yardstick for units in , reality 3 mangoes = 0.01 quintal etc. are expressed in units . but the number of mangoes or apples , are unchanged. On the basis of that theory, here, it is proved practical measure by calculating practical digits to prove different angles related with the problem.
Therefor, I have put forward my views through great social media Blog, Twitter, Facebook, and world famous reliable, helpful site Mendeley Data.(By ELSEVIER) [“Atomic Mass Energy Primary Colour” “Atom to Nucleus” “Atomic Time and Space”] They given acceptance to my work, as a result, this article “ATOMIC MASS ENERGY and CONSTANT”
In this article discussed about source of Quantum digit for light,(Like 3; 3.5; 4; etc.) and rules in previous article, another’s Six no of constant like Honorable scientist ‘Planck’s Constant.
                                                                                              
                                                                                                         .sree Debasish Dasgupta

[Nb:- No part of this publication (including it’s related) may be reproduced or transmitted any means or any information storage and retrieval system, without written permission from the registrar or chip-in-charge .Org. (M.N.G.R.W.S) -  2013]  


ABSTRACT “Atomic Mass Energy and Constant”


Image No 2 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for Example: TABLE:-1, TABLE:-2 and Different Six Constant.


Image No 3 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for Comparing With Planck’s Constant from Different Methods


Image No 4 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for 1st Method Source of Quantum Digit.


Image No 5 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for 2nd Method Source of Quantum Digit.


Image No 6 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for relationship between three phase formula & others


Image No 7 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for 1st process of comparing with used digit and current units


Image No 8 “ATOMIC MASS ENERGY and CONSTANT” sree Debasish Dasgupta Image for 2nd process of comparing with used digit and current units




রবিবার, ২৮ এপ্রিল, ২০১৯

E x M = m2


                                    Energy X Mass = m2
                             Sree Debasish Dasgupta
In past, I have discussed different rule and method of molecules in all Article of Light and structure of light. All thought, No famous journal have published my Articles, but, LOT of scientists have appreciated my Articles and more importantly, lot of science researcher accepted their inability of courageousness  to publish my article on their journal/magazines.
I can SAY it with confidence that all the social media for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my project article on Data cite of them.
I can not find any expression to congratulate them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their gratitude to my work. 

   Introduction :    In, the present article for support and favour  of past articles E=F/s, and unavoidably others articles.
A Story Of Latest Scientific Discovery”  “Atomic Mass Energy Primary Colours”   “Atomic Time Space” and Also Latest Article
         “ Atom to Nucleus” 
I have discussed new logic and formulae which have to be understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search and also I request to study each article discussed in the past.
                         Without, unit power I have shown only numbers [Like : approx mass of one particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616 unit]  the whole calculation to express present unit by using 10, or multiple of 10,
As per my calculation :
One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit , Here (M / m) = 1.054 unit  ( All Approximate unit).
One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.
Here (M-m) = 0.1 unit.
One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit , Here (E / e)= 1.062 unit.
 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit , Here (E - e)= 0.09 unit. (Please see ‘Atom to Nucleus’ for Details)
(All unit Constant for Nuclear action and reaction,  All unit Approximate).
#                        E2 = E x M x (E – e) / (M – m)  
For  example: [(1.602 x 1.78) x 0.09 ] / 0.1 = 2.566404 unit. = E2 ,
  Root Over 2.566404 = 1.602 unit.= E,
#                          M2 = [ (E x M) / (E – e)] x (M – m)
Examp:  [ (1.602 x 1.78) / 0.09 ] x 0.1 = 3.1684 ( it is acceleration of ‘f’ either energy). Root Over 3.1684 = 1.78 unit, = M.
#                             E = [ M / (M – m) ] x (E – e)
Examp :  [ (1.78 / 0.1) x 0.09 = 1.602 unit. = E.
#                             M = [ E x (M – m) ] / (E – e)
Examp : [ (1.602 x 0.1) / 0.09 = 1.78 unit = M,
#                              E x M = m2
Examp : 1.602 x 1.78 = 1.68862  unit  = m2 
Hence : m2  = m x m, one ‘m’ for mass and others ‘m’ is equivalent  energy which is internal (sleeping) Energy of Mass. This Energy create Mass to mass.
Example   ( 1.602 x root over (10/9) = 1.6886 unit
                        Or,   m = E x (M / m) = 1.602 x 1.054 = 1.6885...unit .
                        Same for   m x (E/e) = M,
This process is continue, so we can create many  different type of formula, for mystery or World.
Conclusion :-
1.   One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit ,
One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.
One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit ,
 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit ,
2.   E2 = E x M x (E – e) / (M – m), 
3.   M2 = [ (E x M) / (E – e)] x (M – m)
4.   E = [ M / (M – m) ] x (E – e)  
5.   E x M = m2  Or, m = E x (M / m) & m x (E/e) = M,





  






Energy X Mass = m2


শুক্রবার, ২৬ এপ্রিল, ২০১৯




                   ATOM to NUCLEUS
                                   Sree DEBASISH DASGUPTA

In past, I have discussed different rule and method of molecules in all Article of Light and structure of light. All thought, No famous journal have published my Articles, but, LOT of scientists have appreciated my Articles and more importantly, lot of science researcher accepted their inability of courageousness  to publish my article on their journal/magazines.
I can SAY it with confidence that all the social media for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my project article on Data cite of them.
I can not find any expression to congratulate them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their gratitude to my work.  

      
   Introduction :    In, the present article for support and favour  of past articles E=F/s, and unavoidably others articles.
I have discussed new logic and formulae which have to be understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search and also I request to study each article discussed in the past.
                         Without, unit power I have shown only numbers [Like : approx mass of one particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616 unit]  the whole calculation to express present unit by using 10, or multiple of 10,
                                                 
                                             F= root over 9M/r
We know F=mv2/r. mv2/r= G.M.m/r2, or, v2=G.M/r, or, v= root over G.M/r, or  v2r=G.M, or, G=v2r/M
[F=force, G=Gravity, M=mass v=velocity, r=radius,  as per my past calculation F=5.3…, G=0.53…, M=1.679616, velocity=1.296, (and Time = 3600 sec./1000=3.6, space 360 degree/ 1000= 0.36, 3.6x0.36= 1.296 all ready explain about time and space)]
 * F = mv2/r, = (1.679616 x 1.2962) / 0.53 = 5.3…, unit.
 * mv2/r = G.M.m/r2, or, v2=G.M/r, = 0.53 x 1.679616 / 0.53 = 1.679616 unit.
Or, v= root over G.M/r = 1.296 = root 1.679616, (Orbital velocity of atom)
Or, v2r =G.M = (v)1.2962 x (r) 0.53 = G.M. = 1.679616 x 0.53 = (G) 0.53 x (M)1.679616  
Or, G= v2 r/M, G= 1.2962 x 0.53 / 1.679616, = G = 0.53.
.*    w = v/r = root over G.M / r3, (orbital angular velocity of atom ‘w’)
Or, w = 1.296/0.53 = 2.44528. or w =  root over G.M / r3 = root 0.53 x 1.679616 / 0.533
Or  G.M = root over [ (0.53 x 1.67616) / (0.53 x 0.53 x 0.53)] = 2.44528 = w .
Now as per this calculation  :
F= mv2 / r, root over mc2 / r, or F = root over 9m / r. (as per my calculation c2 = 9)
[see also : as per E = m – (m/10) rule. E=1.679616 – 0.1679616, = 1.511644. unit.
And 1.6021736179 x (10/9) = 16.021736179 / 9 = 1.7801929087.
1.78019290872 = 3.16908679246, 3.16908679246 x 0.53 = 1.679616 (same value M)
3.16908679246 / 0.53 = 5.979409, root 5.979409 = 2.44528 (same value ‘w’)
(3.169086792462 = 10, 3.16908679246 it is nearer of plank h ber,)

Next Calculation see image of ‘ATOM to NUCLEUS’
Conclusion : -
1.   4/3 Pi = (Binding Energy of Proton or Neutron) / (mass X Acceleration) 
2.   0.1 unit and 0.09 unit is constant unit.
3.   Force = Root over (9 mass / r either 9mass / G.
4.   m / r = f (acceleration) either (m/G= f ) etc.

Reference : -
‘A Story Of Latest Scientific Discovery’ 1st part, ‘Atomic Mass Energy Primary Colours’  ‘Atomic Gravity’ ‘Atomic Time Space’ and Google.com,








  

  






 


রবিবার, ১৭ মার্চ, ২০১৯


“Atomic Time – Space”

is published on great social media (Facebook, Twitter, Blogs) and “MENDELEY DATA” (By Elsevier.com).
I have get highly enthusiastic and hopeful after its publication. PLEASE READ MY ALL ARTICLES.
Published: 7 Mar 2019 | Version 2 | DOI: 10.17632/c5tg973twk.2
Contributor(s): 
·         sree DEBASISH DASGUPTA