বৃহস্পতিবার, ২৮ জুন, ২০১৮
রবিবার, ১৭ জুন, ২০১৮
SUPPORTING CLUE for E = F/s
F = Es or E = F/s or s =
F/E.
Sree DEBASISH DASGUPTA
* SUPPORTING CLUE for E = F/s *
We know one proton is 1837 time heavier than
electron, and one neutron mass value equal energy = 938 MeV.
So
939/1837= 0.511 unit energy equal of one mass of electron.(And angel 11.25 / 22 = 0.51113 ).
When
collusion with one “L” that moment – 0.511 x 0.413334 = 0.2112796 add one time
and space 0.2112796 + 1.296 = 1.5072796 unit energy. As per my opinion E = m –
(m/10).
Mass = ( ex10) / 9 = (1.50728 x10) / 9 =
15.0728 / 9 = 1.674755 unit mass.
And again 1.5072796 x 9 = 13.56 unit energy (
as per Scientist ‘Bhore’ I have several time write about that in my article in
short “ASOLSD” see also picture 6)
1837 X 5.334 (Force) = 9798.588.Root = (i) 98.98766 Root = (ii) 9.94925 Root = (iii)
3.15424 Root = (iv) 1.776 Root = (v) 1.332
..(i) nearer 100 (ii) nearer 10,(iii) nearer
‘Pi’. Or ‘h’ bar (iv) mass (v) 4/3, (as per my opinion see about digit “10” )
1837 x 1.602 (energy) = 2942.874 Thirty two(32,
max electron in one orbit) Root = 1.283509 x 7 = 8.98456 (C2 as per
my calculation)
1837 x 1.296 (Time & Space) = 2380.75
Twenty seven (3x3x3=27) Root = 1.3337=(4/3) for details read my all article at
Facebook, Twitter, Blog’s By google search.A Story Of Latest Scientific
Discovery.
Now ---1837 x 1.11* (see latter) = 1935
Sixteen Root = 1.6047 (energy), Square = 2.5754 Square = 6.63273 (Planck
Constant) Square = 43.98 =14 x Pi ,(See About 42/3=14 , in my article)
*** That means 1839
times ,Force, energy, time etc. present in a neutron.***
[ So Total Force x energy x time & space = 9798.588 x 2942.874 x 2380.75 = 68651330478.747, 68651330478.747 nine Root (9) = 16, [ SEE Picture No
9,& 9A]
And when add total time 1935 , 68651330478.747 x 1935= 1328 4032 4476375.445, if we Root it
step by step after 7th step we will get see 1.289254, 1.289254 x 7 =
“9”, ( or Root 128, For Why 128 ?, 0.53 x 100 = 53, & 53 / *0.413334* =
128. & 3 x 3 =”9” , 3 x 3 x 3 = 27) and
if 1328 4032 4476375.445 twenty seven
(27, 3x3x3 = 27) Root = 3.33, (Displacement) Next … several time I write about 1.289254 in
my article ASOLSD.
So that means : (1328
4032 4476375.445 / 1.289254 ) = 103036581213923.28043969613435366
times 1.289254 is present in a neutron .
Let us see : - step by step Root to 103036581213923.28043969613435366
,after sixth (6th) step (or 64 Root over) we will get result 1.65559 ,we know one
neutron 1839 times heavier than one electron, 1839 x 9 = 16551 divided by
10,000 = 1.6551 it same uint.And after 7th step (or 128 Root over)
get resut 1.2866976140160393105164440327068 x 7 = “9”
Again if Nine Root 103036581213923.28 get result
36, (36 x 10 = 360 degree angle 36 x 100 = 3600 sec. Time.) AND (27) twenty
seven ROOT GET 3.3, For clear understand see picture 9 & 9A ]
*1.11 to the power 32** = 28.2056 Root (as
per a2 +b2=c2= 28.17 & 5.31 is10 times of ‘H’
atoms 1st orbit radius, 0.53, or as per my opinion force OR Force
for revolving electron around the orbit)
As per formula c = Root over (a2 +
b2 + 2ab) = Root over (a + b)2 = a + b
..a + b = (4.13334 + 3.33) = 7.46334, Root
7.46334 = 2.73191 Root = 1.653 Root = 1.285632.
1.285632 x 7 = 8.999 or “9”. (4L=
0.413334x4=1.653336)
Please see details of ‘7.46334’at “A Story Of Latest Scientific Discovery”,
IOSRPHR Journal Vol-8,Issue-5,Version-1 Page No.28, OR Social Media by *GOOGLE*
search.
As per my view *1.11 is Time need for create Displacement
to Acceleration. In the time of revolving electron around the orbit. So Time =
Root 1.11=1.05365 unit.
We know Force = mass x f (Acceleration) = mass x (changing motion /
Time) = Momentum/Time, ie changing of Momentum = Force x Time.
So factor of time & mass, as per my view
E= F/s or s = F/E. or F = Es [Force=5.334, Energy = 1.602, Displacement (s) =
3.33, Time = 1.05365,Time square= 1.11 ]
Here Acceleration = (3.33 /1.11) = 3 unit.
So as per law F = ma, m=F/a or mass=5.334/3=
1.778 unit. [When Time is 1.11]
We know As per law P=mf or P = mass x (v – u)
/ time,[Here v= end & u= starting motion, ]
P = 1.782662 mass x (3.33 – 3 = 0.33) / 1.11
= 0.58828 / 1.11 or 0.53 it is radius of “H” atom’s 1st orbit. And
this total calculation makes from 0.53…unit.
NOW – see also –
(a) 1/3 = 0.33…,
(b) 5.334 / 1.05356 = 5.06283458 , 5.06283458
four Root = 1.5 it is ½ of 3, (some time we use ½ spin ext.)
© 3.33 / 1.296 (Time & Space) =
2.569,Root 2.569 = 1.6029 unit, all most one energy.
(d) 3.33 / 0.413334 = 8.056321, 8.056321
eight Root = 1.297 all most 1.296 (Time & Place)
(e) 5.3 + 1.2919 (constant of Visible Light)
= 6.5919, 6.5919 sixteen Root = 1.125 x 10 =11.25 angle. [ already explain
about 11.25 & 1.125 in my article ]
(f) 5.334
+ 1.2919 = 6.625 Planck constant. Root = 1.6044 unit energy, [Please see
COSMOSGONY 1&2, and “E = m – (m/10)” articles ]
## (g)
32** Root = 5.6568, Root = 2.378, Root 1.54221,Root 1.1241,Root = 1.11, Root=
1.055 It is time for produce an atom from Neutron. Four Root 1.24eV= 1.055.,Force=
5.334, Root sixteen 5.334 = 1.11.
[except
32 All are already explain in COSMOGONY & others article SEE also E = F/S,
‘Pic 9’ ]
[ Establish My all opinion & all formula
and also L= 0.413334,all most TRUE]
For details please see my all articles, “A
STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE
SEARCEH.
[ No Part of
ALL this publication may be reproduce or any form or any means or any
information without permission from the author or chip in charge :by:-
M.N.G.R.W.S ]
শনিবার, ৯ জুন, ২০১৮
E =
F/s
Energy = Force divided by Displacement (s)
Author
sree Debasish Dasgupta
[ ‘Universe’
– Process of formation is maker of Digit. For easy understanding to compare of
microscopic matter, WE make variety of UNIT’s. “It born by virtue one’s own
qualities.” Method of creation and work of creation can’t follow up variety of
UNIT. Each and every ROOT, SQUARE.etc indicate part by part internal action and
reaction collision etc. And confirmed that GREAT SCIENTIST Sir “NEWTON”s 1st,2nd,3rd
laws.]
3L =1.24
electron Volt. (L=0.413334 ,10L= 4.13334 see latter)
Source of
‘7’ ---- (1.24124)^9 =7
(6.99) [1.24124 to the power 9 = 7].
4.13334
Joule = 2.579828079 x 10^+19 eV,
2.579828079
/2 = 1.2899, 1.2899 x 7 = 9 [Source of 9].
[we know
898,755,178,736,880 m^2,,s^2 = C^2, as per my
opinion C^2 = 8.98755178736880]
9/7 =
1.2857 or 8.98755178736880 / 6.99 = 1.28757.
1.28757 x
4.13334 = 5.322 (see latter) x 4.13334 = 21.99 or 22 [source of 22]
Or 1.28757
x 4.13334^2 (square) = 22.
That means
one eV to the power 9 = 7 , and (9 divided by 7 ) into 4.13334 square = 22.
10L^2 X (9/7) = 22
Or { (1.28757 x 7) / 1.24124^9 } x (4.13334)2
= 22
Or {(1.28757
x 1.24124^9 ) / (1.24124)^9 } x (4.13334)2 =22
Or 1.28757 x 4.13334^2 =22
Or 1.28757
x ( 3.33 x 1.24124)^2 = 22 [see latter about 3.33]
So one Pi
= (1.28757 x 3.33 x 3.33 x 1.24124 x 1.24124 ) / (1.24124 x 1.24124 x 1.24124 x
1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124)
Or one Pi
= (1.28757 x 3.33 x 3.33) / (1.24124)^7 or (1.28757 x 3.33 x 3.33) /
4.535
Now step by step we can see in which process
create one mass of atom
One L=0.413334 x 3 = 1.24 eV, one constant =
1.29219 x 1.24 = 1.601956 or 1.602 unit charge or energy. 1.6019/3= 0.533 (A0)unit
it is average Radius of 1st orbit of one Atom’s.
[ 0.534 x 2 = 1.0668 it is Time and Place
1.0668^4 = 1.296 as per my view it is Time & Place see my all
articles about time and Place]
0.53 x2 x 3.14(Pi) = 3.33
[Source of 3.33 , it is average circumference
when electron revolving around the orbit ]
So 3.33 is “Displacement” of electron’s.= [S]
3.33 x 1.24124 = 4.13334 [ Source of 10L, see
article Cosmogony 1&2 and Others]
3.33 x 1.601956 (eng) = 5.334 it is Average
“FORCE” for when electron revolving around the orbit. = [F] 10 times of Bhore’
‘H’ atom’s 1st orbit.
We know Work = Fs [F= Force & s=
Displacement]
If s=0 in that moment W=Fs=0 (because S=0)
But is it POSSIBLE !! Question arise … without energy can’t
make’s any WORK, and when complete any work in that moment definitely it’s take
some TIME, So where is absorbed
Energy, Time etc.?
My OPINION
Energy = Force / Displacement
(s)
Let us see as per this rule “E”=F/s
“E” = 5.334 (F) / 3.33 (s)
or “E” = 1.602 unit *PROVED*
Actually it
elastic Collision, Force = Energy x Displacement,
or
Displacement = Force / Energy
Any of one “0” means particular in that moment is
starting or ending point of new alternative
changing period of Energy to another Energy.
Due to Law
of “Conservation of Energy” and “Transformation of Energy”
See also as
per rule 4/3x ‘Pi’x ‘r’ cube.
4/3x3.14x0.53^3
cube= 0.623614 it’s equivalent Energy 9.9914x 10^-20 Joule. And
electron Volt = 3.89 x10^+18 eV note Red color frequency is 3.8757
unit.
See also as
per a^2 + b^2 = c^2
[a=4.13334, b=3.33, c=5.3…]
4.13334^2
+ 3.33^2 = 5.3…or 17.0845 + 11.089 = 28.1735
See also Two
dimensional reference frame :-
AC = root
over ( AB square + BC square )
[AC = 5.3..AB=
4.13334, BC= 3.33]
5.3…= root
over 4.13334^2 + 3.33^2 = root 28.1765 = 0.53
[See Picture No ; ‘ASOLSD’ – 9]
[ hare is
shown that value of some digit or quantity is change like 5.34,5.334,5.3
1.602,1.601959 etc. because for variety of element and variety of atom so this
calculation done by average value ]
For details
please see my all articles, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at
FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH. and also all picture “ASOLSD”
[ No Part of
ALL this publication may be reproduce or any form or any means or any
information without permission from the author or chip in charge :by:- M.N.G.R.W.S
]
বিজ্ঞানের ভাষা
Sree DEBASISH DASGUPTA
আমি দেখেছি বা দেখছি যখনি কোন ছাত্র বা ব্যক্তি
বিজ্ঞান বিষয়ে কিছু আলোচনা করে তখন বেশি ভাগ সময় তারা অসহায় ভাবে বলে বিজ্ঞান
বুঝিনা ,বা আমি বিজ্ঞান বিষয় নিয়ে পড়াশোনা করিনি।
তাদের নিজেদের মধ্যে ভাবনাটাই এমন স্থানে দাঁড়িয়েছে যে বিজ্ঞান হচ্ছে বিশেষ
বিশেষ মানুষের জন্য।
তার জগৎ ও আলাদা, এটা দূর করতেই - বিজ্ঞান
বিষয়টি অনুধাবন করতে যাতে সহজ হয় সেই দিকে নজর দিয়ে আমি প্রতিটি প্রবন্ধ রচনা করার
চেষ্টা করেছি।।
আজ বিজ্ঞান একটি ভয়ঙ্কর স্থানে
প্রতিষ্ঠিত হবার কারণ নানা রকম বাধা নিষেধের ঘেরাটোপে রেখে সাধারণের কাছে পরিবেষণই
দায়ি।।
আমি নিজে এর ভুক্তভুগি –
সামান্য একটি প্রবন্ধ (যদি তা অতি নিন্মমানের ও হয়) কোন প্রতিষ্ঠিত জার্নালে প্রকাশ করতে হলে তাদের দেওয়া
নির্দেশ অনুযায়ী – ভাগ ভাগ করে প্রতি ভাগের আবার আলাদা আলাদা পরিমাণের,ডিজাইনের, অক্ষর
ইত্যাদি নানা ফরমান মানতে হবে তবেই তারা লেখাটি পড়বেন,তারপর অনেক ধাপ পেরুলে তবে
হয়তো প্রকাশের বিবেচনা করা হতেপারে।
যদি লেখাতেই এত নির্দেশ মানতে হয় এবং তা প্রকাশ করতে প্রতি জার্নালের জন্য বিভিন্ন পদ্ধতি প্রশিক্ষণ গ্রহণ করতে হয়, তবে
সহজেই অনুমান করা যাবে বিজ্ঞান চর্চার মধ্যে কত বাধা,কেমন ভাবে একে সাধারনের বোধের
অনুপযুক্ত করা হয়েছে।।
আমি একটি প্রতিষ্ঠিত জার্নালের আমার লেখা “A STORY OF LATEST SCIENTIFIC DISCOVERY” প্রত্যাক্ষানের ভাষা নিবেদন করছি।। তারা পড়েই দেখেননি! হতে পারে অতি নিন্মমানের।।
Dear Debasish,
Thank you for your email and apologies for
the delayed reply. This paper was rejected on 17th May
without peer review, on the grounds that it
is not scientifically sound. Therefore, we do not require any further
correspondence regarding this paper. Furthermore, as per our appeal policy, it
will not be entitled to an appeal, as the paper was not sent for peer review.
We thank you for
submitting your paper to Royal Society Open Science.
Best wishes,
Thadcha
জানিনা এটা অতি শিক্ষার অহংকারের বহিঃপ্রকাশ কিনা।
আবার অন্য একটি বৃহৎ সংস্থার লেখার উদারহণ দিচ্ছি যা
আমাকে উৎসাহ দান করেছিল ,NASA – একটি বিশেষ গুনের অধিকারী, তারা যে কোন অবহেলিত বিষয়ের দিকে নজর রাখেন, যদি
সেই অবহেলিত বিষয় থেকে মুল্যবান কিছু বেরিয়ে আসে সেই উদ্দেশ্যে। আর তার মুল্যও
দিতে জানেন।এই মহৎ গুণই তাদের প্রতিনিয়ত উত্থানের অন্যতম কারণ।।
<nssc-sp-cust-sat@mail.nasa.gov>
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