Happy New Year 2019

                                              “Atomic Time – Space”

                                .sree Debasish Dasgupua.

              

ABSTRACT :

After long wait and hard work “A Story Of Latest Scientific Discovery” Article’s next article “ATOMIC MASS - ENERGY - PRIMARY- COLOUR” is published on great social media (Facebook, Twitter, Blogs) and “MENDELEY DATA” (By Elsevier.com).

I have get highly enthusiastic and hopeful after its publication. If all the successful people accept my hard work, then only I will succeed in my work.

“Atomic – Time Space & Energy Mass” next part, I have only shown how Mass Energy and Force etc. is divided and joined. If we have to understand, then, we have to read every article minutely, then it will be easy. (link: https://data.mendeley.com/datasets/358bfdjvwg/1

 ) “10” and “9” both are shown in relation to time & space with Picture.

I have given special emphasis on how the subject is easy and understand to all common people. 

INTRODUCTION :

 All calculation done without any power.

 like one mass = 1.782662 x 10^{^-36} Kg, one energy = 1.6021766208 x 10^{^-19} Joule, here 1.782662 and 1.6021766208.

That means if compare to current unit 

This total calculation should be multiplied (or divided) by 10 or, multiplier of 10 like 1000,10000,10,0000 to convert it from current unit to different unit like- Kilogram, gram, meter, second, etc. As per need. 

                                                      Time and Place

Every element are created from the collaboration of different energy. This energy known as heat energy, magnetic energy , light energy etc.are already mentioned in my article. These two energy “time” & “place”.

   Every elements are transformed into magnetic waves after dissolve or perish. Everyday billion  and billion of magnetic waves have given birth to one or more than one wave’s Addition or subtraction to Elements or matter.

    In this “Time” & “Place” are particular, Like ,if we heat one cup of water it will turn into vapor or if we cool then it will become ice .

Here place is particularly fixed be it, water, or vapor, or ice .

Question arises of “Time’s low of Constancy”

If we increase the quantity of heat to make vapor of a cup of water then it will quickly turn into vapor or if we slowly decrease the heat then it will take time to become ice.

  The main exponent of experiment is “Heat”

 To create heat we need elements and in that element the amount of ‘energy’ and the “time & place”(Which is absorb) is always equal to the total (abandon energy)  “energy” - “Time” - “place’s quantity of the changed element from its previous status.

 The changed quantity of ‘Time’ ‘Place’ and ‘energy’ is gained or lost from the heat creating element by transformation.

Now, we can see that to make the structure of any material or, matter in the world there is a relation between energy to particle or, particle to energy in the same way there is a relation between time and place.

“This universe have definite time & place. Like different type of energy (Light, heat, magnetic etc). Time and place are also different type of energy. Time and place has also the potential to change from one energy to another”.

For Example- Thousand Light away, if a BlackHole creates then the time and place will change definitely.

Every substance creates in delicate wavelength’s shape and size- different matter one or more substance. It’s total quantity is equal- total place is equal- total time is equal.

# Again, when we analyze white Light through a prism then we get 7 (seven) different colours.

The shape of the prism is triangular so, the upper part is thin and in the lower part it is getting thicker only to stop the wavelength of light – Upper thin part have less obstacle but, in the lower part i.e. the thin part of the lower prism gives more obstacle to the wavelength of light. So, the lower part to upper part is doing the change of place, same as the change of time.

Now, we have to see what is the role of change of time & place in structure making of a substance.

[As per, math’s Unitary Method ]

When one Mass = 1.782662 unit and one Energy = 1.60217 unit

As per this when Mass =1 unit in that moment Energy = (1.60217 / 1.782662) = 0.9 unit

As per rule Energy = Mass – (mass /10)

When Mass = 1 unit then Energy = 1 – (1/10)

Or Energy = 1-(0.1) = 0.9 unit

[ Let’s see as per Sphere and circle rule, The area of circle of is radius = ‘r’ is Pi x ‘r’ square and circumference of circle = 2 x Pi x ‘r’, similarly surface area of sphere = 4 x Pi x ‘r’ square and Volume=(4/3) x Pi x ‘r’ cube, relation with Time x space=(3600 Sec / 1000)= 3.6, (360 Degree / 1000 ) = 0.36,  3.6 x 0.36 = 1.296 ]

  One mass of neutron 1.674929 unit (without any power) mass area of neutron =  (4 x Pi x ‘r’) =

4 x 3.14159 x ‘r’ sqr = 1.674929 or ‘r’ sqr = 1.674929 / 12.566 or ‘r’ sqr = 0.1333 or

‘r’ = root over 0.1333 or ‘r’ = 0.365, [ 0.365 x 2 = 73 ]

Pi x ‘r’ square = 1.674929, or ‘r’ square = 1.674929 / 3.14159 or ‘r’ square = 0.533, ‘r’ = 0.73.

0.73 root cube = 0.9,

[ That means 0.9 cube = 0.73, and 0.73 square = 0.533 unit same of 1^st radius of ‘H’ atoms ]

     #  10 root = 3.16227766, 3.16227766 x 4 = 12.6491106, 12.6491106 square = 160

As per (4/3) x pi x r or 10 [root eihgt (8)] = 1.333 x pi x 1.296 (time x space)

1.333 x 3.14259 x 1.296 = 5.4286721, 5.4286721 cube = 160

    # [ see equivalent quantity of Joule & eV.

160 Joule = 10 (x 10⁺²⁰ ) Electron Volt.

  (1) 5.41286721 eV = 8.697691 x 10^-19 Joule.

 (One photon eV 1.24 unit X 7 = 8.68 unit)

(2) 5.41286721 x 1.60217662 (one Energy) = 8.697691 unit

(3) 5.41286721 Joule = 3.3883 x 10⁺¹⁹ eV.

     5.41286721 / 1.60217662 = = 3.3883 unit ]

Force 5.334 / 4 = 1.3335, (=4/3), 1.3335 square = 1.778279, 1.778279 square = 3.16227766,

3.16227766 square = 10, 10 root = 3.16227766,  3.16227766 / 3 = 1.05409255 (time),

1.05409255 square = 1.111111, 1.111111 x 9 = 10,

For next calculation see Picture (below) 

    Conclusion : 10 Energy = 9 Mass :

 

 

I’m happy to share my achievements to my well wishers as my long struggle to establish my scientific research in any International Organization ; finally its been published in ‘MENDELEY DATA’

Please search at the site of “Mendeley Data” or Google.

Link :  https://data.mendeley.com/datasets/358bfdjvwg/1

MENDELEY DATA

Atomic Mass – Energy-Primary Colour

Published: 1 Dec 2018 | Version 1 | DOI: 10.17632/358bfdjvwg.1

Contributor(s): 

sree DEBASISH DASGUPTA

[nb.> “A STORY OF LATEST SCIENTIFIC DICOVERY’’—‘ASOLSD’ and related artiale by sree Debasish Dasgupta # No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge ]

                                              Husk of Potato

                       .sree Debasish Dasgupta.                      

Abstract

After lot of permutation – combination deduced some rule [ Electron Volt = Frequency x 0.413334, Energy = Mass - (mass /10), Energy = Force / Displacement etc.]   from the article, “A STORY OF LATEST SCIENTIFIC DISCOVERY” (in short  “ASOLSD”) and it’s related. That every matter creates or destroys in two parts. Both of them are quite opposite to each other in principle.

As per this, every organic cell or, plant life (Botany) every matter has its waste products which obstructs the growth of creation of the ‘living cell’. It can be seen by following the cell that if we want to control any Virus or, germ can be destroyed by using their own waste on them in a proper method. They can be destroyed totally in this method. By this, lot of fatal diseases like AIDS, Cancer, Jaundice, etc. can be controlled by deducing their Anti-dote or, method of over come through it.

Experiment:

It feel through this experiment that in human body to control the Diabetic limit by ‘potato husk’.

First, have to take out the peel out of the potato, then, it have to take that particular husk to be washed properly and to be eaten at a particular limit so, that some type blood starch to be controlled.

Dose: 25 – 40 gram weight potato husk to be boiled or, to be fried in light oil or, paste of potato husk and it can be eaten in morning time at breakfast or, in lunch at noon time food. If it is needed, can eat it two times a day… as per blood sugar test result.  

After 3 to 7 days Diabetic problem are in control, then it should minimise the quantity slowly.

    Conclusion

 Some type blood starch to be controlled.

It is possible, because this potato husk is just the opposite starch of that starch creating element. If it is used in body, it will work as opposite starch of the Diabetic element present in body.

[nb.> “A STORY OF LATEST SCIENTIFIC DICOVERY’’—‘ASOLSD’ and related artiale by sree Debasish Dasgupta # No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge ]

Image of “Atomic Gravity”sree Debasish Dasgupta

“Atomic Gravity”

                              “Atomic Gravity”

                                  Sree Debasish Dasgupta

We are indebted to those scientist .[ The great “Einstein”, sir “Newton”, “Bhore” and lot of others Scientist ] who given new direction to our knowledge by doing hard work relentlessly day by day .I am making out some investigations after checking out some contributions by themIt is not my any kind of self – importance and also have not any mentality to – disrespect  to any scientist.

AS I am not beigin a PROFETIONAL SCIENTIST –From that point of view it seems

After the broadcast (In SOCIAL media) of my discovery lot of derogatory and defame comments are heard- [This paper was  rejected on without peer review, on the grounds that it is not scientifically sound…Like this] --- which was cause that no organization give me recognition. It is to dishearten. MY GRIEF.

I take it as my own social responsibility to attract all the views of honorable scientist of the world. I have tried my responsibility with best of my abilities. It’s my ardent wish that my scientific formulas are being used for the benefit of human society  Rest, all depends on your opinions about my research (thought).

## Honorable scientist Bhore, as per his opinion it is seen that every orbit of an Atom moves around in a particular rule.(pic-7).My opinion is that every electron’s radius is same with proton’s radius’s ,proton’s radius = electron’s radius’s Induction area.

As per this view,

In my article  F = Es or E = F/s or s = F/E. (picture no ASOLSD 9 & 9A)  we have discussed on different calculation of  “Neutron” ‘Proton’ ‘Electron’s Force, Energy,etc in Atom's orbit .

NOW – As per great scientist Honorable NEWTON’s law of Gravitation,

G₁= F x r ^² / m^{^2}

G₂= F x r ^² / m₁m₂  

[ as per my (sree Debasish Dasgupta) calculation : Force = 5.3…unit, Radius = Atomic distance here 0.53 unit, mass = atomic mass, like Neutron, Proton, Electron etc.] 

 We know one Neutron mass = 1.6749 x 10^{^-27} Kg. and one Neutron 1839 times heavier than Electron.

So as per my view One Electron mass   1.6749 / 1839 = 0.0009 unit. One Electron mass 

Hare ‘F’= 5.3…unit, mass= 1.6749, ‘r’= 0.53unit, (as per scientist Bhore ‘H’ atom’s 1^st orbit radius.) Electron mass= 0.000904 unit (as per my calculation electron mass 9.04unit or 0.000904 unit, For details Please see “A STORY OF LATEST SCIENTIFIC DISCOVERY)

Gravitation of  Neutron ---

G = F x r ^² / m^{^2}  

‘G’₁ =(F) 5.3… x (r) 0.53^²… / (1.6749)^{^2} = 0.53..unit That means ‘G’ for an Atom is 0.53…unit,

Again as per G= F x r ^² / m₁m₂ ‘G’ or Attraction or Repulsion between Neutron and Electron.

‘G’₂ =(F) 5.33 x r (0.533)^² / (N)1.6749 x (e) 0.000904 = 1.5141 / 0.0015141= 1000unit .

As per law “g” = GM / R^{^2}

“g” (neutron) =(0.533 x 1.6749) / 0.533^{^2} =(0.8927217 / 0.284089) = 3.1424 or one Pi

“g” (electron) =(0.533 x 0.000904) / 0.533^{^2} = 0.000481832 / 0.284089 = 0.001696 unit.

Now “g” (neutron) x “g” (electron) = 3.1424 x 0.001696 = 0.00533 unit.

{“g”(n) x “g”(e)} x “G” = (3.1424…x 0.001696) x 1000 = 0.00533 x 1000 = 5.33 unit Force. 

[ as per “G”₂ – 1000 root = 31.6227766,root 31.6227766 = 5.6234, 5.624 x 2 = 11.25 (nearer) as per my calculation it is minimum Angel of electron see my all article.

Again as per Coulomb rule electric field and intensity of on electric field ---

(a) ‘E’ = Q / k.‘r’^{^2} = “E” = 1.602 / 0.5334 = 5.63 x 2 = 11.25 (nearer) .

Root 5.624 = 2.371 already explain about 2.371 and it’s next calculation in “COSMOGONY” part 1&2,

(b) Force = Q₁ X Q₂ / k.’r’² (k= permittivity or dielectric constant) as per Coulomb rule.

F = (1.602 x 1.602) / (0.5334)^² = 9.02 unit

“E’ = 5.63 as per (a) and ‘Torque’ = p x E or “T” = 5.63 x 1.602 = 9.02.

(Torque on an electric dipole in a uniform electric field)

Please see about “9” in my article.

Conclusion :

[ Transformation of Energy & Law of Conservation of Energy ]

.1) ‘G’1 = Gravitation of  Neutron = 0.53… unit

.2) ‘G’2 = Gravitation between Neutron and Electron = 1000 unit

.3) “g”1 (neutron) = 3.1424 or one Pi

.4) “g”2 (electron) = 0.001696 unit.

.5) “g”1x ‘g’2 x G2 = 5.33 = Force. [see “Atomic Gravity” Image]

*** This total calculation should be multiplied (or divided) by 10 or, multiplier of 10 like 100,1000,10,000 to convert it from current unit to different unit like- Kg, gram, cm,sec, etc. I have done all calculation without any power.

For details please read my all articles at SOCIAL MEDIA, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH. Sree Debasish, sree Debasish Google, scientist sree Debasish, sree Debasish Dasgupta,sree Debasish Nasa, mygov.in sree Debasish etc related and images,

 [nb.> “A STORY OF LATEST SCIENTIFIC DICOVERY’’—‘ASOLSD’ and related artiale by sree Debasish Dasgupta # No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge by:MNGRWS]

এই CERTIFICATE আপনাদের অবদান, তাই সকলকে উৎসর্গ করতে পেরে ধন্য হলাম,

यहि CERTIFICATE   आपकी दान है , आप सबको निबेद्न करताहु  

SUPPORTING CLUE for E = F/s

                       F = Es or E = F/s or s = F/E.

                                              Sree DEBASISH DASGUPTA

                                          * SUPPORTING  CLUE for  E = F/s *

We know one proton is 1837 time heavier than electron, and one neutron mass value equal energy = 938 MeV.

So  939/1837= 0.511 unit energy equal of one mass of electron.(And  angel 11.25 / 22 = 0.51113 ).

 When collusion with one “L” that moment – 0.511 x 0.413334 = 0.2112796 add one time and space 0.2112796 + 1.296 = 1.5072796 unit energy. As per my opinion E = m – (m/10).

Mass = ( ex10) / 9 = (1.50728 x10) / 9 = 15.0728 / 9 = 1.674755 unit mass.

And again 1.5072796 x 9 = 13.56 unit energy ( as per Scientist ‘Bhore’ I have several time write about that in my article in short “ASOLSD” see also picture 6)

1837 X 5.334 (Force) = 9798.588.Root = (i)  98.98766 Root = (ii) 9.94925 Root = (iii) 3.15424 Root = (iv) 1.776 Root = (v) 1.332

..(i) nearer 100 (ii) nearer 10,(iii) nearer ‘Pi’. Or ‘h’ bar (iv) mass (v) 4/3,  (as per my opinion see about digit “10” )

1837 x 1.602 (energy) = 2942.874 Thirty two(32, max electron in one orbit) Root = 1.283509 x 7 = 8.98456 (C² as per my calculation)

1837 x 1.296 (Time & Space) = 2380.75 Twenty seven (3x3x3=27) Root = 1.3337=(4/3) for details read my all article at Facebook, Twitter, Blog’s By google search.A Story Of Latest Scientific Discovery.

Now ---1837 x 1.11* (see latter) = 1935 Sixteen Root = 1.6047 (energy), Square = 2.5754 Square = 6.63273 (Planck Constant) Square = 43.98 =14 x Pi ,(See About 42/3=14 , in my article)

*** That means 1839 times ,Force, energy, time etc. present in a neutron.***

[ So Total Force x energy x time & space =  9798.588 x 2942.874 x 2380.75 = 68651330478.747,  68651330478.747  nine Root (9) = 16, [ SEE Picture No 9,& 9A]

And when add total time 1935 , 68651330478.747  x 1935= 1328 4032 4476375.445, if we Root it step by step after 7^th step we will get see 1.289254, 1.289254 x 7 = “9”, ( or Root 128, For Why 128 ?, 0.53 x 100 = 53, & 53 / *0.413334* = 128. & 3 x 3 =”9” , 3 x 3 x  3 = 27) and if  1328 4032 4476375.445 twenty seven (27, 3x3x3 = 27) Root  = 3.33, (Displacement)  Next … several time I write about 1.289254 in my article ASOLSD.

 So that means : (1328 4032 4476375.445  / 1.289254 ) = 103036581213923.28043969613435366  times 1.289254 is present in a neutron .

Let us see : - step by step Root to  103036581213923.28043969613435366 ,after sixth (6^th) step (or 64 Root over)  we will get result 1.65559 ,we know one neutron 1839 times heavier than one electron, 1839 x 9 = 16551 divided by 10,000 = 1.6551 it same uint.And after 7^th step (or 128 Root over) get resut 1.2866976140160393105164440327068 x 7 = “9”  

Again if Nine Root 103036581213923.28 get result 36, (36 x 10 = 360 degree angle 36 x 100 = 3600 sec. Time.) AND (27) twenty seven ROOT GET 3.3, For clear understand see picture 9 & 9A  ]

*1.11 to the power 32** = 28.2056 Root (as per a² +b²=c²= 28.17 & 5.31 is10 times of ‘H’ atoms 1^st orbit radius, 0.53, or as per my opinion force OR Force for revolving electron around the orbit)

As per formula c = Root over (a² + b² + 2ab) = Root over (a + b)² = a + b

..a + b = (4.13334 + 3.33) = 7.46334, Root 7.46334 = 2.73191 Root = 1.653 Root = 1.285632.

1.285632 x 7 = 8.999 or “9”. (4L= 0.413334x4=1.653336)

Please see details of ‘7.46334’at  “A Story Of Latest Scientific Discovery”, IOSRPHR Journal Vol-8,Issue-5,Version-1 Page No.28, OR Social Media by *GOOGLE* search.

As per my view *1.11 is Time need for create Displacement to Acceleration. In the time of revolving electron around the orbit. So Time = Root 1.11=1.05365 unit.

We know Force = mass x f  (Acceleration) = mass x (changing motion / Time) = Momentum/Time, ie changing of Momentum = Force x Time.

So factor of time & mass, as per my view E= F/s or s = F/E. or F = Es [Force=5.334, Energy = 1.602, Displacement (s) = 3.33, Time = 1.05365,Time square= 1.11 ]

Here Acceleration = (3.33 /1.11) = 3 unit.

So as per law F = ma, m=F/a or mass=5.334/3= 1.778 unit. [When Time is 1.11]

We know As per law P=mf or P = mass x (v – u) / time,[Here v= end & u= starting motion, ]

P = 1.782662 mass x (3.33 – 3 = 0.33) / 1.11 = 0.58828 / 1.11 or 0.53 it is radius of “H” atom’s 1^st orbit. And this total calculation makes from 0.53…unit.

NOW – see also –

(a) 1/3 = 0.33…,

(b) 5.334 / 1.05356 = 5.06283458 , 5.06283458 four Root = 1.5 it is ½ of 3, (some time we use ½ spin ext.)

© 3.33 / 1.296 (Time & Space) = 2.569,Root 2.569 = 1.6029 unit, all most one energy.

(d) 3.33 / 0.413334 = 8.056321, 8.056321 eight Root = 1.297 all most 1.296 (Time & Place)

(e) 5.3 + 1.2919 (constant of Visible Light) = 6.5919, 6.5919 sixteen Root = 1.125 x 10 =11.25 angle. [ already explain about 11.25 & 1.125 in my article ]

(f) 5.334  + 1.2919 = 6.625 Planck constant. Root = 1.6044 unit energy, [Please see COSMOSGONY 1&2, and “E = m – (m/10)” articles ]

##   (g) 32** Root = 5.6568, Root = 2.378, Root 1.54221,Root 1.1241,Root = 1.11, Root= 1.055 It is time for produce an atom from Neutron. Four Root 1.24eV= 1.055.,Force= 5.334, Root sixteen 5.334 = 1.11.

    [except 32 All are already explain in COSMOGONY & others article SEE also E = F/S, ‘Pic 9’ ]

[ Establish My all opinion & all formula and also L= 0.413334,all most TRUE]

 For details please see my all articles, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH.

[ No Part of ALL this publication may be reproduce or any form or any means or any information without permission from the author or chip in charge :by:- M.N.G.R.W.S ]     

 

F = Es or E = F/s or s = F/E. 'ASOLSD' PICTURE No 9A

ENERGY = FORCE/s ,s=Displacement, Picture No ASOLSD 9

                                       E = F/s

                     Energy = Force divided by Displacement (s)

                      Author sree Debasish Dasgupta

[ ‘Universe’ – Process of formation is maker of Digit. For easy understanding to compare of microscopic matter, WE make variety of UNIT’s. “It born by virtue one’s own qualities.” Method of creation and work of creation can’t follow up variety of UNIT. Each and every ROOT, SQUARE.etc indicate part by part internal action and reaction collision etc. And confirmed that GREAT SCIENTIST Sir “NEWTON”s 1^st,2^nd,3^rd laws.]   

3L =1.24 electron Volt. (L=0.413334 ,10L= 4.13334 see latter)

Source of ‘7’ ----  (1.24124)^⁹ =7 (6.99)  [1.24124 to the power 9 = 7].

4.13334 Joule = 2.579828079 x 10^⁺¹⁹ eV,

2.579828079 /2 = 1.2899, 1.2899 x 7 = 9 [Source of 9].

[we know 898,755,178,736,880 m^^2,,s^² = C^², as per my opinion C^² = 8.98755178736880]

9/7 = 1.2857 or 8.98755178736880 / 6.99 = 1.28757.

1.28757 x 4.13334 = 5.322 (see latter) x 4.13334 = 21.99 or 22 [source of 22]

Or 1.28757 x 4.13334^² (square) = 22.

That means one eV to the power 9 = 7 , and (9 divided by 7 ) into 4.13334 square = 22.

 10L^² X (9/7) = 22

Or  { (1.28757 x 7) / 1.24124^⁹ } x (4.13334)² = 22

Or {(1.28757 x 1.24124^⁹ ) / (1.24124)^⁹ } x (4.13334)² =22

Or  1.28757 x 4.13334^² =22

Or 1.28757 x ( 3.33 x 1.24124)^² = 22 [see latter about 3.33]

So one Pi = (1.28757 x 3.33 x 3.33 x 1.24124 x 1.24124 ) / (1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124 x 1.24124)

Or one Pi = (1.28757 x 3.33 x 3.33) / (1.24124)^⁷ or (1.28757 x 3.33 x 3.33) / 4.535

Now step by step we can see in which process create one mass of atom

One L=0.413334 x 3 = 1.24 eV, one constant = 1.29219 x 1.24 = 1.601956 or 1.602 unit charge or energy. 1.6019/3= 0.533 (A⁰)unit it is average Radius of 1^st orbit of one Atom’s.

[ 0.534 x 2 = 1.0668 it is Time and Place 1.0668^{^4} = 1.296 as per my view it is Time & Place see my all articles about time and Place]

0.53 x2 x 3.14(Pi) = 3.33

[Source of 3.33 , it is average circumference when electron revolving around the orbit ]

So 3.33 is “Displacement” of electron’s.= [S]

3.33 x 1.24124 = 4.13334 [ Source of 10L, see article Cosmogony 1&2 and Others]

3.33 x 1.601956 (eng) = 5.334 it is Average “FORCE” for when electron revolving around the orbit. = [F] 10 times of Bhore’ ‘H’ atom’s 1^st orbit.

We know Work = Fs [F= Force & s= Displacement]

If s=0 in that moment W=Fs=0 (because S=0)

But is it POSSIBLE  !! Question arise … without energy can’t make’s any WORK, and when complete any work in that moment definitely it’s take some TIME,      So where is absorbed Energy, Time etc.?

 My OPINION

Energy = Force / Displacement (s)

Let us see  as per this rule “E”=F/s

“E” = 5.334 (F) / 3.33 (s)

or “E” = 1.602 unit  *PROVED*

Actually it elastic Collision, Force = Energy x Displacement,

or Displacement = Force / Energy

Any  of one “0” means particular in that moment is starting or ending point of new  alternative changing period of Energy to another Energy.

Due to Law of “Conservation of Energy” and “Transformation of Energy”  

See also as per rule 4/3x ‘Pi’x ‘r’ cube.

4/3x3.14x0.53^{^3} cube= 0.623614 it’s equivalent Energy 9.9914x 10^{^-20} Joule. And electron Volt = 3.89 x10^{^+18} eV note Red color frequency is 3.8757 unit.

See also as per  a^{^2} + b^{^2} = c^{^2} [a=4.13334, b=3.33, c=5.3…]

4.13334^{^2} + 3.33^{^2} = 5.3…or 17.0845 + 11.089 = 28.1735

See also Two dimensional reference frame :-

AC = root over ( AB square + BC square )

[AC = 5.3..AB= 4.13334, BC= 3.33]

5.3…= root over 4.13334^{^2} + 3.33^{^2} = root 28.1765 = 0.53

            [See Picture No ; ‘ASOLSD’ – 9]

[ hare is shown that value of some digit or quantity is change like 5.34,5.334,5.3 1.602,1.601959 etc. because for variety of element and variety of atom so this calculation done by average value ]

For details please see my all articles, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH. and also all picture “ASOLSD”

[ No Part of ALL this publication may be reproduce or any form or any means or any information without permission from the author or chip in charge :by:- M.N.G.R.W.S ]      

                                                              

     

                            বিজ্ঞানের ভাষা 

                  Sree DEBASISH DASGUPTA

আমি দেখেছি বা দেখছি যখনি কোন ছাত্র বা ব্যক্তি বিজ্ঞান বিষয়ে কিছু আলোচনা করে তখন বেশি ভাগ সময় তারা অসহায় ভাবে বলে বিজ্ঞান বুঝিনা ,বা আমি বিজ্ঞান বিষয় নিয়ে পড়াশোনা করিনি।

তাদের নিজেদের মধ্যে ভাবনাটাই এমন স্থানে দাঁড়িয়েছে যে বিজ্ঞান হচ্ছে বিশেষ বিশেষ মানুষের জন্য।

তার জগৎ ও আলাদা, এটা দূর করতেই - বিজ্ঞান বিষয়টি অনুধাবন করতে যাতে সহজ হয় সেই দিকে নজর দিয়ে আমি প্রতিটি প্রবন্ধ রচনা করার চেষ্টা করেছি।।

 আজ বিজ্ঞান একটি ভয়ঙ্কর স্থানে প্রতিষ্ঠিত হবার কারণ নানা রকম বাধা নিষেধের ঘেরাটোপে রেখে সাধারণের কাছে পরিবেষণই দায়ি।।

আমি নিজে এর ভুক্তভুগি –

সামান্য একটি প্রবন্ধ (যদি তা অতি নিন্মমানের ও হয়) কোন  প্রতিষ্ঠিত জার্নালে প্রকাশ করতে হলে তাদের দেওয়া নির্দেশ অনুযায়ী – ভাগ ভাগ করে প্রতি ভাগের আবার আলাদা আলাদা পরিমাণের,ডিজাইনের, অক্ষর ইত্যাদি নানা ফরমান মানতে হবে তবেই তারা লেখাটি পড়বেন,তারপর অনেক ধাপ পেরুলে তবে হয়তো প্রকাশের বিবেচনা করা হতেপারে।

যদি লেখাতেই এত নির্দেশ মানতে হয় এবং তা প্রকাশ করতে প্রতি জার্নালের জন্য  বিভিন্ন পদ্ধতি প্রশিক্ষণ গ্রহণ করতে হয়, তবে সহজেই অনুমান করা যাবে বিজ্ঞান চর্চার মধ্যে কত বাধা,কেমন ভাবে একে সাধারনের বোধের অনুপযুক্ত করা হয়েছে।।

আমি একটি প্রতিষ্ঠিত জার্নালের আমার লেখা “A STORY OF LATEST SCIENTIFIC DISCOVERY” প্রত্যাক্ষানের ভাষা নিবেদন করছি।। তারা পড়েই দেখেননি! হতে পারে অতি নিন্মমানের।।

Dear Debasish,

Thank you for your email and apologies for the delayed reply. This paper was  rejected on 17^th May without peer review, on the grounds that it is not scientifically sound. Therefore, we do not require any further correspondence regarding this paper. Furthermore, as per our appeal policy, it will not be entitled to an appeal, as the paper was not sent for peer review.

We thank you for submitting your paper to Royal Society Open Science.

Best wishes,

Thadcha

জানিনা এটা অতি শিক্ষার অহংকারের বহিঃপ্রকাশ কিনা।

আবার অন্য একটি বৃহৎ সংস্থার লেখার উদারহণ দিচ্ছি  যা আমাকে উৎসাহ দান করেছিল ,NASA – একটি বিশেষ গুনের অধিকারী, তারা যে কোন অবহেলিত বিষয়ের দিকে নজর রাখেন, যদি সেই অবহেলিত বিষয় থেকে মুল্যবান কিছু বেরিয়ে আসে সেই উদ্দেশ্যে। আর তার মুল্যও দিতে জানেন।এই মহৎ গুণই তাদের প্রতিনিয়ত উত্থানের অন্যতম কারণ।।

Customer Satisfaction and Communications <nssc-sp-cust-sat@mail.nasa.gov>	Tue, Jan 10, 2017 at 10:03 PM
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Dear SREE DEBASISH, We value your opinion! Please do not forget to complete a brief survey from the NASA Shared Services Center (NSSC) concerning the support you received from the NSSC Customer Contact Center. This survey is related to the service you received regarding a case that was resolved for you during January 1, 2017 through January 7, 2017, specifically case number, CALL05xxx, regarding, Inquiry regarding ideas. This survey consists of only five questions, and will take less than one minute of your time. Please note that all the comments in the survey are voluntary. As we collect and tabulate survey results, please be aware that your responses will remain completely confidential, and while your verbatim comments will be collected to further define your level of satisfaction with the NSSC, they are not attributed to specific individuals. However, should you select disagree or strongly disagree as any of your response option; we encourage you to provide your contact information so we can contact you to determine how we can improve our service to you in the future. Please take a moment to give us your honest opinion about the support you received from the Customer Contact Center. Your comments will help to assure we continue to maintain our commitment to provide you with Unparalleled Service. Click here to begin. This survey will be available for your response through January 13, 2017 Thank you The NASA Shared Services Center