রবিবার, ২৮ এপ্রিল, ২০১৯

E x M = m2


                                    Energy X Mass = m2
                             Sree Debasish Dasgupta
In past, I have discussed different rule and method of molecules in all Article of Light and structure of light. All thought, No famous journal have published my Articles, but, LOT of scientists have appreciated my Articles and more importantly, lot of science researcher accepted their inability of courageousness  to publish my article on their journal/magazines.
I can SAY it with confidence that all the social media for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my project article on Data cite of them.
I can not find any expression to congratulate them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their gratitude to my work. 

   Introduction :    In, the present article for support and favour  of past articles E=F/s, and unavoidably others articles.
A Story Of Latest Scientific Discovery”  “Atomic Mass Energy Primary Colours”   “Atomic Time Space” and Also Latest Article
         “ Atom to Nucleus” 
I have discussed new logic and formulae which have to be understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search and also I request to study each article discussed in the past.
                         Without, unit power I have shown only numbers [Like : approx mass of one particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616 unit]  the whole calculation to express present unit by using 10, or multiple of 10,
As per my calculation :
One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit , Here (M / m) = 1.054 unit  ( All Approximate unit).
One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.
Here (M-m) = 0.1 unit.
One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit , Here (E / e)= 1.062 unit.
 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit , Here (E - e)= 0.09 unit. (Please see ‘Atom to Nucleus’ for Details)
(All unit Constant for Nuclear action and reaction,  All unit Approximate).
#                        E2 = E x M x (E – e) / (M – m)  
For  example: [(1.602 x 1.78) x 0.09 ] / 0.1 = 2.566404 unit. = E2 ,
  Root Over 2.566404 = 1.602 unit.= E,
#                          M2 = [ (E x M) / (E – e)] x (M – m)
Examp:  [ (1.602 x 1.78) / 0.09 ] x 0.1 = 3.1684 ( it is acceleration of ‘f’ either energy). Root Over 3.1684 = 1.78 unit, = M.
#                             E = [ M / (M – m) ] x (E – e)
Examp :  [ (1.78 / 0.1) x 0.09 = 1.602 unit. = E.
#                             M = [ E x (M – m) ] / (E – e)
Examp : [ (1.602 x 0.1) / 0.09 = 1.78 unit = M,
#                              E x M = m2
Examp : 1.602 x 1.78 = 1.68862  unit  = m2 
Hence : m2  = m x m, one ‘m’ for mass and others ‘m’ is equivalent  energy which is internal (sleeping) Energy of Mass. This Energy create Mass to mass.
Example   ( 1.602 x root over (10/9) = 1.6886 unit
                        Or,   m = E x (M / m) = 1.602 x 1.054 = 1.6885...unit .
                        Same for   m x (E/e) = M,
This process is continue, so we can create many  different type of formula, for mystery or World.
Conclusion :-
1.   One Mass ( Before Nucleus) Divided by One mass (After Nucleus) = 1.054, Unit ,
One Mass ( Before Nucleus) Minus  One mass (After Nucleus) = 0.1 Unit.
One Energy (After Nucleus) Divided By One energy  (Before Nucleus) = 1.062 unit ,
 One Energy (After Nucleus)  Minus  One energy  (Before Nucleus) = 0.09 unit ,
2.   E2 = E x M x (E – e) / (M – m), 
3.   M2 = [ (E x M) / (E – e)] x (M – m)
4.   E = [ M / (M – m) ] x (E – e)  
5.   E x M = m2  Or, m = E x (M / m) & m x (E/e) = M,





  






Energy X Mass = m2


শুক্রবার, ২৬ এপ্রিল, ২০১৯




                   ATOM to NUCLEUS
                                   Sree DEBASISH DASGUPTA

In past, I have discussed different rule and method of molecules in all Article of Light and structure of light. All thought, No famous journal have published my Articles, but, LOT of scientists have appreciated my Articles and more importantly, lot of science researcher accepted their inability of courageousness  to publish my article on their journal/magazines.
I can SAY it with confidence that all the social media for example ‘Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc. have given LOT of support to my attempt and as a result,
Mendeley.com, (by Elseveier.Com), have published my project article on Data cite of them.
I can not find any expression to congratulate them ( compulsorily : Facebook’; ‘Twitter’, ‘Blog’, GOOGLE etc,) for their gratitude to my work.  

      
   Introduction :    In, the present article for support and favour  of past articles E=F/s, and unavoidably others articles.
I have discussed new logic and formulae which have to be understood through FB, Blog, Twitter, Mendeley.com, ORCID, etc. GOOGLE search and also I request to study each article discussed in the past.
                         Without, unit power I have shown only numbers [Like : approx mass of one particle (Neutron) 1.679616 x 10-27 Kg in that place 1.679616 unit]  the whole calculation to express present unit by using 10, or multiple of 10,
                                                 
                                             F= root over 9M/r
We know F=mv2/r. mv2/r= G.M.m/r2, or, v2=G.M/r, or, v= root over G.M/r, or  v2r=G.M, or, G=v2r/M
[F=force, G=Gravity, M=mass v=velocity, r=radius,  as per my past calculation F=5.3…, G=0.53…, M=1.679616, velocity=1.296, (and Time = 3600 sec./1000=3.6, space 360 degree/ 1000= 0.36, 3.6x0.36= 1.296 all ready explain about time and space)]
 * F = mv2/r, = (1.679616 x 1.2962) / 0.53 = 5.3…, unit.
 * mv2/r = G.M.m/r2, or, v2=G.M/r, = 0.53 x 1.679616 / 0.53 = 1.679616 unit.
Or, v= root over G.M/r = 1.296 = root 1.679616, (Orbital velocity of atom)
Or, v2r =G.M = (v)1.2962 x (r) 0.53 = G.M. = 1.679616 x 0.53 = (G) 0.53 x (M)1.679616  
Or, G= v2 r/M, G= 1.2962 x 0.53 / 1.679616, = G = 0.53.
.*    w = v/r = root over G.M / r3, (orbital angular velocity of atom ‘w’)
Or, w = 1.296/0.53 = 2.44528. or w =  root over G.M / r3 = root 0.53 x 1.679616 / 0.533
Or  G.M = root over [ (0.53 x 1.67616) / (0.53 x 0.53 x 0.53)] = 2.44528 = w .
Now as per this calculation  :
F= mv2 / r, root over mc2 / r, or F = root over 9m / r. (as per my calculation c2 = 9)
[see also : as per E = m – (m/10) rule. E=1.679616 – 0.1679616, = 1.511644. unit.
And 1.6021736179 x (10/9) = 16.021736179 / 9 = 1.7801929087.
1.78019290872 = 3.16908679246, 3.16908679246 x 0.53 = 1.679616 (same value M)
3.16908679246 / 0.53 = 5.979409, root 5.979409 = 2.44528 (same value ‘w’)
(3.169086792462 = 10, 3.16908679246 it is nearer of plank h ber,)

Next Calculation see image of ‘ATOM to NUCLEUS’
Conclusion : -
1.   4/3 Pi = (Binding Energy of Proton or Neutron) / (mass X Acceleration) 
2.   0.1 unit and 0.09 unit is constant unit.
3.   Force = Root over (9 mass / r either 9mass / G.
4.   m / r = f (acceleration) either (m/G= f ) etc.

Reference : -
‘A Story Of Latest Scientific Discovery’ 1st part, ‘Atomic Mass Energy Primary Colours’  ‘Atomic Gravity’ ‘Atomic Time Space’ and Google.com,








  

  






 


রবিবার, ১৭ মার্চ, ২০১৯


“Atomic Time – Space”

is published on great social media (Facebook, Twitter, Blogs) and “MENDELEY DATA” (By Elsevier.com).
I have get highly enthusiastic and hopeful after its publication. PLEASE READ MY ALL ARTICLES.
Published: 7 Mar 2019 | Version 2 | DOI: 10.17632/c5tg973twk.2
Contributor(s): 
·         sree DEBASISH DASGUPTA

সোমবার, ১৭ ডিসেম্বর, ২০১৮


                                              “Atomic Time – Space”
                                .sree Debasish Dasgupua.
              

ABSTRACT :

After long wait and hard work “A Story Of Latest Scientific Discovery” Article’s next article “ATOMIC MASS - ENERGY - PRIMARY- COLOUR” is published on great social media (Facebook, Twitter, Blogs) and “MENDELEY DATA” (By Elsevier.com).
I have get highly enthusiastic and hopeful after its publication. If all the successful people accept my hard work, then only I will succeed in my work.
“Atomic – Time Space & Energy Mass” next part, I have only shown how Mass Energy and Force etc. is divided and joined. If we have to understand, then, we have to read every article minutely, then it will be easy. (link: https://data.mendeley.com/datasets/358bfdjvwg/1
 ) “10” and “9” both are shown in relation to time & space with Picture.
I have given special emphasis on how the subject is easy and understand to all common people. 
INTRODUCTION :

 All calculation done without any power.
 like one mass = 1.782662 x 10^-36 Kg, one energy = 1.6021766208 x 10^-19 Joule, here 1.782662 and 1.6021766208.
That means if compare to current unit 
This total calculation should be multiplied (or divided) by 10 or, multiplier of 10 like 1000,10000,10,0000 to convert it from current unit to different unit like- Kilogram, gram, meter, second, etc. As per need. 

                                                      Time and Place

Every element are created from the collaboration of different energy. This energy known as heat energy, magnetic energy , light energy etc.are already mentioned in my article. These two energy “time” & “place”.
   Every elements are transformed into magnetic waves after dissolve or perish. Everyday billion  and billion of magnetic waves have given birth to one or more than one wave’s Addition or subtraction to Elements or matter.
    In this “Time” & “Place” are particular, Like ,if we heat one cup of water it will turn into vapor or if we cool then it will become ice .
Here place is particularly fixed be it, water, or vapor, or ice .
Question arises of “Time’s low of Constancy”
If we increase the quantity of heat to make vapor of a cup of water then it will quickly turn into vapor or if we slowly decrease the heat then it will take time to become ice.
  The main exponent of experiment is “Heat”
 To create heat we need elements and in that element the amount of ‘energy’ and the “time & place”(Which is absorb) is always equal to the total (abandon energy)  “energy” - “Time” - “place’s quantity of the changed element from its previous status.
 The changed quantity of ‘Time’ ‘Place’ and ‘energy’ is gained or lost from the heat creating element by transformation.
Now, we can see that to make the structure of any material or, matter in the world there is a relation between energy to particle or, particle to energy in the same way there is a relation between time and place.
“This universe have definite time & place. Like different type of energy (Light, heat, magnetic etc). Time and place are also different type of energy. Time and place has also the potential to change from one energy to another”.
For Example- Thousand Light away, if a BlackHole creates then the time and place will change definitely.
Every substance creates in delicate wavelength’s shape and size- different matter one or more substance. It’s total quantity is equal- total place is equal- total time is equal.
# Again, when we analyze white Light through a prism then we get 7 (seven) different colours.
The shape of the prism is triangular so, the upper part is thin and in the lower part it is getting thicker only to stop the wavelength of light – Upper thin part have less obstacle but, in the lower part i.e. the thin part of the lower prism gives more obstacle to the wavelength of light. So, the lower part to upper part is doing the change of place, same as the change of time.
Now, we have to see what is the role of change of time & place in structure making of a substance.

[As per, math’s Unitary Method ]
When one Mass = 1.782662 unit and one Energy = 1.60217 unit
As per this when Mass =1 unit in that moment Energy = (1.60217 / 1.782662) = 0.9 unit
As per rule Energy = Mass – (mass /10)
When Mass = 1 unit then Energy = 1 – (1/10)
Or Energy = 1-(0.1) = 0.9 unit
[ Let’s see as per Sphere and circle rule, The area of circle of is radius = ‘r’ is Pi x ‘r’ square and circumference of circle = 2 x Pi x ‘r’, similarly surface area of sphere = 4 x Pi x ‘r’ square and Volume=(4/3) x Pi x ‘r’ cube, relation with Time x space=(3600 Sec / 1000)= 3.6, (360 Degree / 1000 ) = 0.36,  3.6 x 0.36 = 1.296 ]
  One mass of neutron 1.674929 unit (without any power) mass area of neutron =  (4 x Pi x ‘r’) =
4 x 3.14159 x ‘r’ sqr = 1.674929 or ‘r’ sqr = 1.674929 / 12.566 or ‘r’ sqr = 0.1333 or
‘r’ = root over 0.1333 or ‘r’ = 0.365, [ 0.365 x 2 = 73 ]
Pi x ‘r’ square = 1.674929, or ‘r’ square = 1.674929 / 3.14159 or ‘r’ square = 0.533, ‘r’ = 0.73.
0.73 root cube = 0.9,
[ That means 0.9 cube = 0.73, and 0.73 square = 0.533 unit same of 1st radius of ‘H’ atoms ]
     #  10 root = 3.16227766, 3.16227766 x 4 = 12.6491106, 12.6491106 square = 160
As per (4/3) x pi x r or 10 [root eihgt (8)] = 1.333 x pi x 1.296 (time x space)
1.333 x 3.14259 x 1.296 = 5.4286721, 5.4286721 cube = 160
    # [ see equivalent quantity of Joule & eV.
160 Joule = 10 (x 10+20 ) Electron Volt.
  (1) 5.41286721 eV = 8.697691 x 10-19 Joule.
 (One photon eV 1.24 unit X 7 = 8.68 unit)
(2) 5.41286721 x 1.60217662 (one Energy) = 8.697691 unit
(3) 5.41286721 Joule = 3.3883 x 10+19 eV.
     5.41286721 / 1.60217662 = = 3.3883 unit ]
Force 5.334 / 4 = 1.3335, (=4/3), 1.3335 square = 1.778279, 1.778279 square = 3.16227766,
3.16227766 square = 10, 10 root = 3.16227766,  3.16227766 / 3 = 1.05409255 (time),
1.05409255 square = 1.111111, 1.111111 x 9 = 10,
For next calculation see Picture (below) 
    Conclusion : 10 Energy = 9 Mass :










 

 



মঙ্গলবার, ১১ ডিসেম্বর, ২০১৮


I’m happy to share my achievements to my well wishers as my long struggle to establish my scientific research in any International Organization ; finally its been published in ‘MENDELEY DATA’
Please search at the site of “Mendeley Data” or Google.


MENDELEY DATA

Atomic Mass – Energy-Primary Colour

Published: 1 Dec 2018 | Version 1 | DOI: 10.17632/358bfdjvwg.1
Contributor(s):