sree DEBASISH DASGUPTA: 2026

1️⃣ Proton Energy – Mass Relation (Pythagoras Style)

Sree Debasish Dasgupta

Proton Energy (iA):

$iA=a2+b22×2×(4root>4π)iA = \sqrt{\frac{a^2 + b^2}{2}} \times 2 \times (4\text{root} > 4\pi)$ iA=2a2+b2×2×(4root>4π)

Proton Mass via Energy:

$Proton Mass=[(a2+b2)/(X/Y)]2a+b×iA\text{Proton Mass} = \frac{[(a^2 + b^2) / (X/Y)]^2}{a+b} \times iA$ Proton Mass=a+b[(a2+b2)/(X/Y)]2×iA

Rule for Energy:

$Energy={[4root>4π]×2}×Energy2×Proton Energy\text{Energy} = \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Energy}$ Energy={[4root>4π]×2}×2Energy×Proton Energy

Rule for Mass:

$Mass={[4root>4π]×2}×Energy2×Proton Mass\text{Mass} = \{[4\text{root} > 4\pi] \times 2\} \times \sqrt{\frac{\text{Energy}}{2}} \times \text{Proton Mass}$ Mass={[4root>4π]×2}×2Energy×Proton Mass

2️⃣ Root 3 Cube – Time – Mass Relation

Cube of Root 3 multiplied by 4:

$X=(3)3×4X = (\sqrt{3})^3 \times 4$ X=(3)3×4

Time Ratios:

$X/Y=432/3600=0.12,Y/X=3600/432=8.3333X/Y = 432 / 3600 = 0.12, \quad Y/X = 3600 / 432 = 8.3333$ X/Y=432/3600=0.12,Y/X=3600/432=8.3333

Mass Calculation using Energy & Time:

$(CX/Y)2=Mass,[C×(Y/X)]2=Mass\left(\frac{C}{X/Y}\right)^2 = \text{Mass}, \quad [C \times (Y/X)]^2 = \text{Mass}$ (X/YC)2=Mass,[C×(Y/X)]2=Mass

3️⃣ Electron Mass & Energy Distribution in 360° Orbit

Unit Energy per Degree:

$∘Energy=1.60217653×10−19360=4.45049×10−22 Unit1^\circ \text{Energy} = \frac{1.60217653 \times 10^{-19}}{360} = 4.45049 \times 10^{-22} \, \text{Unit}$ 1∘Energy=3601.60217653×10−19=4.45049×10−22Unit

Energy per Electron (Minimum 11.25° Angle):

$Eelectron=11.25×4.45049×10−22=5.0068×10−21 UnitE_{\text{electron}} = 11.25 \times 4.45049 \times 10^{-22} = 5.0068 \times 10^{-21} \, \text{Unit}$ Eelectron=11.25×4.45049×10−22=5.0068×10−21Unit

Time per Degree:

$∘×10×3=112.5 secT_{1^\circ} = 3600/360 = 10 \, \text{sec}, \quad \text{Electron Induction Time} = 3.75^\circ \times 10 \times 3 = 112.5 \, \text{sec}$ T1∘=3600/360=10sec,Electron Induction Time=3.75∘×10×3=112.5sec

Energy-Time Interaction:

$E×T×(0.5333)2=1.60217653×10−19 Unit EnergyE \times T \times (0.5333)^2 = 1.60217653 \times 10^{-19} \, \text{Unit Energy}$ E×T×(0.5333)2=1.60217653×10−19Unit Energy

4️⃣ Mass–Energy Conversion Formula

Fundamental Rule:

$E=m−m10E = m - \frac{m}{10}$ E=m−10m

Digit-Based Mass Relation:

$m×109≈1.78262 Unit Massm \times \frac{10}{9} \approx 1.78262 \, \text{Unit Mass}$ m×910≈1.78262Unit Mass

Small Unit Mass:

$1.78262/1036=1.78262×10−36 Unit Mass1.78262 / 10^{36} = 1.78262 \times 10^{-36} \, \text{Unit Mass}$ 1.78262/1036=1.78262×10−36Unit Mass

Useful Conversion:

$1.60436×10−39×16→1.60217653×10−19 Unit Energy1.60436 \times 10^{-39} \times 16 \rightarrow 1.60217653 \times 10^{-19} \, \text{Unit Energy}$ 1.60436×10−39×16→1.60217653×10−19Unit Energy

5️⃣ Proton & Electron Mass via Interaction Chains

Proton Mass via Interaction:

$Proton Mass×iA=1.782662×10−36 Unit Mass\text{Proton Mass} \times iA = 1.782662 \times 10^{-36} \, \text{Unit Mass}$ Proton Mass×iA=1.782662×10−36Unit Mass

Electron–Neutron Mass Relation:

$mNeutron=9.11214×10−31×1838=1.67481×10−27 Unitm_{\text{Neutron}} = 9.11214 \times 10^{-31} \times 1838 = 1.67481 \times 10^{-27} \, \text{Unit}$ mNeutron=9.11214×10−31×1838=1.67481×10−27Unit

Mass Calculation Using Energy-Time:

$Mass=[C/(X/Y)]2or[C×(Y/X)]2\text{Mass} = [C / (X/Y)]^2 \quad \text{or} \quad [C \times (Y/X)]^2$ Mass=[C/(X/Y)]2or[C×(Y/X)]2

sree DEBASISH DASGUPTA

মঙ্গলবার, ৩১ মার্চ, ২০২৬

Physics Formulas – Proton, Electron, Mass & Energy Relations

1️⃣ Proton Energy – Mass Relation (Pythagoras Style)