The relationship of Energy with Atoms and Time, Space ©
sree Debasish Dasgupta
In each of the previous articles, electrons, protons, etc., the relationship of ‘L’
with particle and light has
been shown. It also provides detailed information on why each number used in
physics is being used, and what sources are used to find the source.
In the present article, too, are electrons,
protons, Pi, time,
space, how they come together, and what is the source of ‘C’2? (in the great formula e=mC2 . I respect sir Einstein’s
contribution) .This has been discussed.
I look at each article from different angles and from different
perspectives; I have tried to prove their authenticity by calculating the
atomic and light constants, quantum etc. by mathematics. All of these articles
were later published in Mendely Data.
Which has taken a place in the court of the world (scientist community) today through social media.
And how the properties of matter/particles are hidden in all these
combinations of Atom
Therefore, I urge all readers to read each of the previous
articles once to understand this article better or to know the details.
INTRODUCTION
:
This article discusses relation between atomic mass and energy with
electric charge of electron and Proton’s. Here, it is found
that, by comparing with e=mc2 .
Which gives a new
process of calculation about atomic structure, ‘Pi’; electron mass, and also C^2 = Speed of Light Square. in great equation
e=mc2 .
In present essay, have shown the digit or number
‘L’ = 0.413334 used with Proton mass, electron mass, energy, Pi, etc.
And also have shown that how to involve Time 3600
second with Proton mass, electron mass & energy,
1.01
As per
reference articles, ‘L’ = (photon’s eV 1.24 unit / 3) = 0.413334,
(0.413334
*10) ^2 = 17.084449955556
, either [L x (Time /space)] = [0.413334 * (3600/360)]^2
=17.084449955556 [3600 second & 360 Degree ]
9.109390
e-31/17.084449955556 = 5.3319773382798041975309487724255e-32
(Electron
mass) / (0.413334 *10) ^2 = 5.3319773382798041975309487724255e-32 ---- (1a)
1.02
22/7
= 3.1428571428571428571428571428571 [Pi]
1.2985270578788836
/0.413334 = 3.141592653589793242268964082316
[1.2985270578788836
is constant unit and ‘L’ = 0.413334, see reference articles]
(3.1428571428571428571428571428571)^9
= 2.9917256660402129603928590571842e+4
--- (2a)
1.03
2.9917256660402129603928590571842e+4
/ 5.3319773382798041975309487724255e-32
=
5.6109121930465663243853382177961e+35 [2a
/ 1a] --- (3a)
1/5.6109121930465663243853382177961e+35 = 1.7822414e-36 Unit Mass.
As per (e=mc^2) equation. (Mass = 1.782662e-36 Kg. When energy = 1.60217653e-19
J. )
Either
5.3319773382798041975309487724255e-32
/ 2.9917256660402129603928590571842e+4
—
(1a)/(2a) .
=
1.7822414e-36 Unit mass.
So
[ (Electron mass) / (0.413334 *10) ^2 ] divided by (Pi)^9
= Mass. --- (i)
[As per (e=mc^2) equation. Mass = 1.782662e-36 Unit. When energy = 1.60217653e-19
Unit ]
2.01
5.3319773382798041975309487724255e-32
* 2.9917256660402129603928590571842e+4
=
1.5951813453676469100727741096844e-27 = (1a)x(2a).
1.5951813453676469100727741096844e-27 *
(3.1428571428571428571428571428571 /3)
=
1.6711423618137253343619538291932e-27 Unit.
Proton’s mass.
So, [(Electron mass) / ( ‘L’ x 10 )^2 ] x [(Pi) / 3 ] *(Pi)^9 = Proton’s
mass. …(ii)
As per (e=mc^2) equation. Proton’s mass = 1.672623e-27 Kg.
2.02 About ( Pi) with charge and energy,
[We know, 1.5032784196545335010226279575152e-10
Unit = Proton’s energy
As per “e=mc^2 .”
And 1.60217653e-19 Unit electric charge of a Proton then
(-1.60217653e-19) Unit electric charge of an electron]
1.60217653e-19 <root =
4.0027197378782342122581519961685e-10
4.0027197378782342122581519961685e-10 /
1.5032784196545335010226279575152e-10 = 2.6626602800551704435263034591073 /2 =
(1.3313301400275852217631517295536) ^2 =
(1.7724399417458696743044966223555) ^2 = 3.1415433470961018845922239897721
=[Pi].
So. {[(Root> charge of a Proton) /
(Proton’s energy in Joule)] / 2}^4 = [Pi].
[Nb. Please see, Rule:- 3, {[(root > Energy) / Proton energy ] / 2 }^4
= Pi
(here
Energy = 1.60217653e-19 Unit) In reference article ‘Mass Energy in Pythagoras formula’]
Back
calculation
3.1415433470961018845922239897721
<4root = 1.3313353638003897127975349179503
1.3313353638003897127975349179503
*2 = 2.6626707276007794255950698359006
1.5032784196545335010226279575152e-10 * 2.6626707276007794255950698359006
=
4.0027354434480865514832910049719e-10 square.
=
1.6021891030235550091508407813388e-19 , Unit ]
So, {[4Root over > (Pi)] x (Proton’s energy as per e=mc^2)
x 2}^2 = Proton’s electric
charge. …(iii)
Or,
[
x (1.50327841965…5152e-10) x 2]^2 = Proton’s electric charge =1.602189e-19 ,
Unit
[Nb. Rule:-2
[root> (1.60217653e-19 / 2)] / 4root> 4Pi = Proton Energy.
In reference article ‘Mass
Energy in Pythagoras formula’
As per this
view: we can put in place of Proton’s electric charge =1.602189e-19 ,
[root> {[4Root over > (Pi)] x
(Proton’s energy as per e=mc^2) x 2}^2 / 2 x (1 / 4root> 4Pi) = Proton Energy. in Joule.
In this process we can make a lot of new rule. For example Please see image 1 ]
3.01
Next
>
(root
3)^3 =
5.1961524227066318805823390245176 * (10)^2 = 5.1961524227066318805823390245176e+2
(5.1961524227066318805823390245176e+2)^4
= 7.29e+10
0.413334
/ 7.29e+10 =
5.6698765432098765432098765432099e-12 ……(1b)
5.6698765432098765432098765432099e-12
* 1.60217653e-19
= 9.0841431255283950617283950617284e-31 electron
mass.
9.0841431255283950617283950617284e-31
*[ (10/9)^2 * 0.413334*3600 (second)] =
1.6687934287320679526610673400061e-27 Unit. Mass.
3.02
## We know ,
Proton
mass = 1.672623e-27 Unit & energy = 1.5032784196545335010226279575152e-10
(Energy = 1.60217653e-19 Unit, Mass = 1.782662e-36 Unit as per e=mc2)
Electron
mass = 9.109390 x 10^-31 Kg. or 9.109390 e-31 Unit.
Neutron mass = 1.6749274171e-27 Kg or
1.6749e-27 Unit.
Electron
energy in MeV. Unit =0.51099895 MeV.
0.51099895 MeV = 0.51099895 * 1000000 = 5.1099895e+5 electron Volt.
[10 /9=1.1111111111111111111111111111111 root =
1.2345679012345679012345679012346*0.413334=0.51028888888888878683111111111112
As per my (sree Debasish Dasgupta) formula ‘eV=frequency *
0.413334’
1.2345679012345679
is ‘frequency’ and 0.51028888 is ‘eV’
Almost
same Digits (0.51…) of electron’s energy in MeV. Unit. For why used (9 & 10) in my (sree Debasish Dasgupta)
formula, e=m–(m/10)]
Now as per
unitary process:
When energy
is 1.60217653e-19 Unit in that moment electron’s mass = 9.109390 e-31 Unit.
When
energy is 1 Unit ,,
,, ,, ,,
mass = 9.109390 e-31/1.60217653e-19 = 5.6856344038443753760392433160908e-12 Unit. …… (2b)
When
energy (Proton) is 1.5032784196545335010226279575152e-10 Unit ,, ,, ,,
mass = 8.5470915013446183292177653419436e-22 Unit. …… (3b)
(Proton energy) x (2b) =
1.5032784196545335010226279575152e-10 *
5.6856344038443753760392433160908e-12
= 8.5470915013446183292177653419436e-22
8.5470915013446183292177653419436e-22 /
5.1099928085077260860443538932226e+5
=
1.672623e-27 Unit [Energy of me
= 0.51099895000(15)MeV. Unit]
[Nb.
Almost same value 3.01 equation. ……(1b) & (2b) ]
So,
[(Proton energy) x (1b)] / electron energy (eV,) = Proton mass.
Or,
[(Proton energy) x (electron mass/electron’s or, Proton charge)] / electron energy (eV,) =
Proton mass. ……….…(iv)
Example:
(electron’s energy 0.51099895 Mev = (0.51099895 * 1000000) = 510998.95 eV.)
8.5470915013446183292177653419436e-22 / 510998.95 =
1.6726240829544988946098158013717e-27 Unit Proton mass.
[Nb, 8.5470915013446183292177653419436e-22 /
0.5334 (H, Atom’s 1st orbit radius 0.53 Unit)
1.6023793590822306578960939898657e-21
*100 = 1.6023793590822306578960939898657e-19 unit charge of Proton.]
## 510998.95 eV
/
5.6856344038443753760392433160908e-12 =
8.9875449897813519895404631923762e+16
= SPEED of LIGHT Square. [As per ‘e=mc^2’ ]
So we can write here
(electron energy) / (electron
mass/electron’s or, Proton’s charge) = SPEED of LIGHT Square. ……………(v)
4.01
Electron mass X electron MeV. X 3600 Second =
9.109390
e-31 * 0.51 *3600 = 1.672484004e-27 Unit Proton Mass.
So, we can
write here, Proton Mass. / (electron MeV.
X 3600 Second) = Electron mass ….(vi)
Example,
1.672623e-27 / (0.51099895 *3600)
=9.0923376652731e-31 = Electron mass
Or Neutron mass 1.6749274171e-27 / (0.51099895 *3600) =9.1048644201932530607178568783969e-31Unit = Electron
mass
Or,
(0.51099895 *3600) = 1.6749274171e-27 / 9.1048644201932530607178568783969e-31
Or,
(0.51099895 *3600) = 1839.59622
Or, 0.51099895 =
(1839.59622 / 3600) = 0.51099895
Either
number of Proton Mass divided by (electron MeV. X 3600 Second) = number of Electron
mass.
For
example = 3 * 1.672623e-27
/ (0.51099895 *3600)
= 2.7277012995819267339003338460872e-30 = 3
number of Electron
mass.
(2.7277012995819267339003338460872e-30 / 9.0923376652731e-31 = 3 )
Either
number of Proton Mass divided by {[ (10/9)^2 * 0.413334 ] * 3600} = number of Electron
mass …………. (vii)
For
example = 3 * 1.672623e-27
/ (0.510288889 * 3600) = 2.7314968639264258015227919258105e-30 = 3 number of Electron
mass.
[
2.7314968639264258015227919258105e-30 / 3 = 9.105e-31 one Electron
mass.]
Same
method for energy value
For
example
Proton
energy = 1.5032784196545335010226279575152e-10 Unit.
1.5032784196545335010226279575152e-10 / (0.510288889 * 3600) =
8.1831556162479166287762448959421e-14 Unit energy of electron.
So Proton
energy = electron energy * (0.510288889
* 3600) or electron
energy *1837.
For
example 8.1831556162479166287762448959421e-14 * 1837 =
1.5032456867047422847061961873846e-10 Unit.
So in MeV. Unit,
Proton energy = {[ (10/9)^2 * 0.413334
] * 3600} * electron’s energy ……….(viii)
(0.51099895 Mev is electron’s energy mass energy)
For example , {[ (10/9)^2 * 0.413334
] * 3600} * 0.51099895
Or, 1837.04 * 0.51099895 = 938.725511108 Mev ,
Proton energy.
As per formula ‘eV=frequency * 0.413334’
1.2345679012345679
is ‘frequency’ and 0.51028888 is ‘eV’ …. (3.02)
SO.
Photon (1.2345679012345679 )‘frequency’ and ‘L’ (= 0.413334) and 3600
second present in the digit of 1837.04’
And (electron energy in MeV.) x (Time in Second) = {[ (10/9)^2 * 0.413334 ] * 3600}
Ie. (Photon frequency) x (L) x (Time) x (electron energy MeV) =
Proton energy ….(ix)
For example
(1.2345679012345679) * (0.413334) * (3600) * (0.51099695) =938.721837028
MeV.
Conclusion:
·
[ (Electron mass) / (0.413334 *10) ^2 ] divided by (Pi)^9
= Mass.
·
{[(Root> charge of a Proton) /
(Proton’s energy in Joule)] / 2}^4 = [Pi].
·
[(Electron mass) / ( ‘L’ x 10 )^2 ] x [(Pi) / 3 ] *(Pi)^9 = Proton’s
mass.
·
{[4Root over > (Pi)] x (Proton’s energy as per e=mc^2)
x 2}^2 = Proton’s electric
charge
·
[(Proton energy) x (electron mass/electron’s or, Proton charge)] / electron energy (eV,) =
Proton mass.
·
(electron energy) / (electron mass/electron’s or, Proton’s charge) = SPEED of LIGHT
Square
·
Proton
Mass. / (electron MeV. X 3600 Second) = Electron mass
·
Number of
Proton Mass divided by {[ (10/9)^2 * 0.413334 ] * 3600} = Number of Electron
mass
·
Proton energy = {[ (10/9)^2 * 0.413334
] * 3600} * electron’s energy
·
(Photon frequency) x (L) x (Time) x (electron energy MeV) = Proton
energy
Reference:
1) “Atomic Mass
Energy Primary Colour”
2) ‘Mass
Energy in Pythagoras
formula’
3) ‘Atom to
Nucleus’
4) “Atomic Time
Space”
5) ‘Atomic Mass
Energy and Constant’
