Image of “Atomic Gravity”sree Debasish Dasgupta

“Atomic Gravity”

                              “Atomic Gravity”

                                  Sree Debasish Dasgupta

We are indebted to those scientist .[ The great “Einstein”, sir “Newton”, “Bhore” and lot of others Scientist ] who given new direction to our knowledge by doing hard work relentlessly day by day .I am making out some investigations after checking out some contributions by themIt is not my any kind of self – importance and also have not any mentality to – disrespect  to any scientist.

AS I am not beigin a PROFETIONAL SCIENTIST –From that point of view it seems

After the broadcast (In SOCIAL media) of my discovery lot of derogatory and defame comments are heard- [This paper was  rejected on without peer review, on the grounds that it is not scientifically sound…Like this] --- which was cause that no organization give me recognition. It is to dishearten. MY GRIEF.

I take it as my own social responsibility to attract all the views of honorable scientist of the world. I have tried my responsibility with best of my abilities. It’s my ardent wish that my scientific formulas are being used for the benefit of human society  Rest, all depends on your opinions about my research (thought).

## Honorable scientist Bhore, as per his opinion it is seen that every orbit of an Atom moves around in a particular rule.(pic-7).My opinion is that every electron’s radius is same with proton’s radius’s ,proton’s radius = electron’s radius’s Induction area.

As per this view,

In my article  F = Es or E = F/s or s = F/E. (picture no ASOLSD 9 & 9A)  we have discussed on different calculation of  “Neutron” ‘Proton’ ‘Electron’s Force, Energy,etc in Atom's orbit .

NOW – As per great scientist Honorable NEWTON’s law of Gravitation,

G₁= F x r ^² / m^{^2}

G₂= F x r ^² / m₁m₂  

[ as per my (sree Debasish Dasgupta) calculation : Force = 5.3…unit, Radius = Atomic distance here 0.53 unit, mass = atomic mass, like Neutron, Proton, Electron etc.] 

 We know one Neutron mass = 1.6749 x 10^{^-27} Kg. and one Neutron 1839 times heavier than Electron.

So as per my view One Electron mass   1.6749 / 1839 = 0.0009 unit. One Electron mass 

Hare ‘F’= 5.3…unit, mass= 1.6749, ‘r’= 0.53unit, (as per scientist Bhore ‘H’ atom’s 1^st orbit radius.) Electron mass= 0.000904 unit (as per my calculation electron mass 9.04unit or 0.000904 unit, For details Please see “A STORY OF LATEST SCIENTIFIC DISCOVERY)

Gravitation of  Neutron ---

G = F x r ^² / m^{^2}  

‘G’₁ =(F) 5.3… x (r) 0.53^²… / (1.6749)^{^2} = 0.53..unit That means ‘G’ for an Atom is 0.53…unit,

Again as per G= F x r ^² / m₁m₂ ‘G’ or Attraction or Repulsion between Neutron and Electron.

‘G’₂ =(F) 5.33 x r (0.533)^² / (N)1.6749 x (e) 0.000904 = 1.5141 / 0.0015141= 1000unit .

As per law “g” = GM / R^{^2}

“g” (neutron) =(0.533 x 1.6749) / 0.533^{^2} =(0.8927217 / 0.284089) = 3.1424 or one Pi

“g” (electron) =(0.533 x 0.000904) / 0.533^{^2} = 0.000481832 / 0.284089 = 0.001696 unit.

Now “g” (neutron) x “g” (electron) = 3.1424 x 0.001696 = 0.00533 unit.

{“g”(n) x “g”(e)} x “G” = (3.1424…x 0.001696) x 1000 = 0.00533 x 1000 = 5.33 unit Force. 

[ as per “G”₂ – 1000 root = 31.6227766,root 31.6227766 = 5.6234, 5.624 x 2 = 11.25 (nearer) as per my calculation it is minimum Angel of electron see my all article.

Again as per Coulomb rule electric field and intensity of on electric field ---

(a) ‘E’ = Q / k.‘r’^{^2} = “E” = 1.602 / 0.5334 = 5.63 x 2 = 11.25 (nearer) .

Root 5.624 = 2.371 already explain about 2.371 and it’s next calculation in “COSMOGONY” part 1&2,

(b) Force = Q₁ X Q₂ / k.’r’² (k= permittivity or dielectric constant) as per Coulomb rule.

F = (1.602 x 1.602) / (0.5334)^² = 9.02 unit

“E’ = 5.63 as per (a) and ‘Torque’ = p x E or “T” = 5.63 x 1.602 = 9.02.

(Torque on an electric dipole in a uniform electric field)

Please see about “9” in my article.

Conclusion :

[ Transformation of Energy & Law of Conservation of Energy ]

.1) ‘G’1 = Gravitation of  Neutron = 0.53… unit

.2) ‘G’2 = Gravitation between Neutron and Electron = 1000 unit

.3) “g”1 (neutron) = 3.1424 or one Pi

.4) “g”2 (electron) = 0.001696 unit.

.5) “g”1x ‘g’2 x G2 = 5.33 = Force. [see “Atomic Gravity” Image]

*** This total calculation should be multiplied (or divided) by 10 or, multiplier of 10 like 100,1000,10,000 to convert it from current unit to different unit like- Kg, gram, cm,sec, etc. I have done all calculation without any power.

For details please read my all articles at SOCIAL MEDIA, “A STORY OF LATEST SCIENTIFIC DISCOVERY” at FACEBOOK, TWITTER, BLOG by GOOGLE SEARCEH. Sree Debasish, sree Debasish Google, scientist sree Debasish, sree Debasish Dasgupta,sree Debasish Nasa, mygov.in sree Debasish etc related and images,

 [nb.> “A STORY OF LATEST SCIENTIFIC DICOVERY’’—‘ASOLSD’ and related artiale by sree Debasish Dasgupta # No part of this publication may be reproduced or any form or any means or any information,  without permission from the Author or chief in charge by:MNGRWS]