PICTURE No- 5 (ASOLSD)
সোমবার, ২৮ নভেম্বর, ২০১৬
“A
STORY OF LATEST
SCIENTIFIC DISCOVERY’’
“ Sree Debasish Dasgupta”
Today , the whole world is dependent on science. We are indebted to those scientist
who given new direction to our knowledge by doing hard work relentlessly day by
day .I am making out some investigations after checking out some contributions
by them.These investigations are very small and nothing. Here we get all
calculation’s also considered original or base or origin number has taken ,for
examp- mass of electron 9 x 10^-29 gm…one charge is 1.602 x 10^-19 culamb, -13
electro volt in that place 9 unit,1.602 unit, 13 unit ext.ext. has been kept as
a unit. Today,we make different units in multiple of 10 or divisible to 10 for
easy understanding. But it should be said that I am also to take the previous
count only for returning to principal unit,or to make it equal with present
unit.
[
LET US SEE THE MATTER UNDER MAGNIFYING GLASS IN MAGNIFIED POSITION for easy
understanding ]
THE TROPIC OF INVESTIGATION :TO PROVED :-
(A)Visible
light and atoms different quantum digit
,wave length, frequency, charge, energy, orbit,
(B)
Original or main color is four “Red”& “Yellow” (T1 group), “Green”&
“Blue” (T2 group) .
(C) The proof of my discovered rules – (energy
or eV =frequency x 0.413334,)& (Mass x charge = eV) etc.
By
this we can make out the wave length ,frequency, or shall make out the count
directly.
(D)
The mother number or mass, which is shown as “L”,
Page No-1
(L=0.413334) The
whole calculation is done by keeping the energy of photon =1.24 eV, whole wave length field is known as a
triangle, area ½ x base x height, The
area of triangle =3 X 0.413334 = 1.24
sqare unit and 1.602 / 1.24=1.2919 is constant.The main and primitive triangle is
seen as an area of the triangle or ,to calculate the light wave length by
multiplying it with 1000000. As ,1.24 x 1000000=1240000.divided by 4 ,each area
is calculated,so 1240000/4 =31000 which is shown in picture no.5.
It is seen two Red‘s are inside T1 group, Again if we add up the frequency or
quantum no. of “Red” & “Yellow” and divide by 2 we will get frequency of
“Orenge”. Same T2 group “green” + “Blue”
divide by 2 we will get frequency of “Cyan”color.
Apart from this ,to help
geometrical shape drawing we can get same area as by dividing it with 2
to wave length of Red and multiply it with quantum of “Red”, same by dividing it with 2 to wave length of
Yellow and multiply it with quantum of Yellow. (This same area consisting
triangle met when Orange is created, ) as
we add up (both area R&Y) and
dividing it with quantum of Orange we can get wave length of Orange.
Same process for (T2 group) Cyan color .So original color
is four it is proved.
T1 group’s Red,Orange ,Yellow’s addition of frequency is
less than of T2 group, which is equal to
Red frequency quality,so,one more “Red” is in T1 group.So T1,group’s
total number is four,(Red ,Red ,Orange, Yellow).
From 1st law,it is seen that each T1,T2, &
T3,group’s energy is if added then,T1 + T2 + T3, now,T1,& T2 group’s every
addition of mass inside the wave length is =, Hare ,[pic 6]
[ Page no-2]
0.413334 which is small to smallest 0.413334 x 4=1.6534 unitary mass which is near to the hydrogen
atomic molecular Atomic mass.
Electron which is revolving in an orbit unitary mass is 9
unit [which can see and use in different calculation later]
In pic.5A no [except T3 group ] we will get a list of
T1,T2’s energy ,mass.It is proved that if we divide charg to total mass which
is equal to total energy.
## If we look at the principle of scientists Bhor &
Balmer (pic 6) one ‘H’ atom or atom’s energy is given according to each orbit.
In this picture ,the middle part of the two orbits is shown by the energy house
[which is seen on 7,1,2,3,..number]
Again Bhor’s orbit is known as A,B,C, ext.so here,first
orbit middle part and 7 no house/cell’s centre.[Bhor 1st orbit =A]
Now same process of visible light we can get 1st
& 3rd quantum or frequency addition is divided by 2 and we will
get frequency or quantum no of 2nd cell’s. same way T2 group’s 4th
& 6th cell’s quantum or frequency addition is divided by 2 and
we will get frequency or quantum no of 5th cell’s.
In T3 group 7th cell’s quantum no = 1st
& 6th cell’s quantum addition is divided by 2 and we will get
quantum. And other way for T3 we can see pic. 6A. Page No –3
It is proved that every energy status is changed by
following one rule. And three group’s are totally separate.
## Four group’s in an atom mass, energy and charge always
change among each other and transform to another energy from one as energy
universality rule. Every energy is encompassed in a sickle after each and every
action or, reaction. Which is shown in
pic. 6A.
If we pick this 0.1335 unit as frequency,then according
to 1st rule,it’s energy =0,1335 x 0.413334=0.055 unit is multiplied
by 10 then,it is equal to electron weight by a special unit (.055amu). Then ,if
we calculate this as frequency then , it is equal to unitary unit.
Again ,if we multiply it with 0.1335 x 4 = 1.2919 then
all 01.2919unit’s are equal to constant.
So- one neutron is the source of one “H”atom then 2 “electron” means mass or energy is the
replacement of one electron mass =9unit (one still mass of “e” =9.1 unit)
# One newtron is heavier than 1839 time’s.9 x 1839 =
16551 unit.
## One proton is heavier than one electron 1837 times. 9
x 1837=16533.unit.
1 newtron’s mass is eqal to 939.7 energy
1 proton’s mass is eqal to 938.7 energy
So, it is easily presumed that 2nd energy or,2nd
mass is the main component of electron and proton of the concerned ENERGY of
electron . Which is stored in the
“CHAIN’’ of the concerned electron. [Page No—4]
IF WE SEE,THE
MASS OF “e” FROM ANOTHER VIEW
Mass of ‘e’ 9.1 unit
equivalent to energy = 0.511unit
Mass of ,, ,, 1
unit ,, ,,,,,,,,,,,,,,,,,,,,,,,,=0.511/9.1 =.0.0567
1 energy X “L”= 1.24 x 0.413334= 0.51253 or 0.51253/
0.0567 =9.04 unit (Mass)
1 charge X energy X ‘’L’’ = 1.602 x 13.6 =21.787 or 21.787 x 0.413334=9 unit (One unit mass)
Or ,1 constant X 7 = 1.2919 x 7=9.04(one unit mass.)
So ,in every aspect 9 unit mass is present.
*#* By ensuring that calculation we get the new rules---
(A) 1.2919 x 0.413334=0.534 unt“H” atom’s 1st
cell radius.
(B) 1.602 /
0.413334= 3.875 Visible light’s Red frequency .
(C) 1.602 x
0.413334 =0.6621 x 10 =Almost Plank’s constant.
(1.6028 x
0.413334= 0.6625 x 10 =6.625 )
(D) 0.413334x4=1.6533
mass unit (1 proton is heavier than 1 electron then , 1837 (=1837 X 9 = 16533) so, if we calculate by dividing it with 10000 Then
,we get the used unit
(E) 1 stagnant electron’s mass =9.1 unit we get -,,9.1/7=1.299 or 1.299/0.413334=3.1427=π (one pi )
(F) 1.602 X 13.6 =21.787/7 = 3.11 ,,3.11X0.413334=1.285
(energy) and 9/7 = 1.285.(mass
(G) Relation with
the Pythagoras Theory -- Pythagoras Formula – a^2 + b^2 = c^2
Charge^2 + L^2 =
Mass^2 (or Weight ^2)
(Newtron’s Mass= 9 X 1839= 16551,unit /10000=1.6551)
Or-- 1.602^2 + 0.413334 ^2= 1.6551^2
Or-- 2.566404 + 0.170845 = 2.73937 Or--
2.7373249 = 2.74 Or-- 2.74 = 2.74 (PROVED)
Which is the actual relation between Pythagoras main and ancient rules.
[nb.>No part of this publication may be reproduced or
any form or any means or any information,
without permission from the Author or chief in charge ]
[Page-5]
ASOLSD
(A STORY OF LATEST SCIENTIFIC
DISCOVERY->ASOLSD)
Sree DEBASISH
DASGUPTA
The number and digit’s which has been
used in my calculations are taken different text books,net,and are derived from
THE MOTHER NUMBER OR PARTICLE that say “L”.(L=0.413334)
And if the
said digits are CORRECT, then my calculation will be TRUE.
IT IS NOT MY
AUDACITY---I THINK ITs OUR LIABILITY TO ENLIGHT and DEVELOP OUR SOCIETY and
SCIENCE by means of our KNOWLEDGE.
AS I am not
being a PROFESSIONAL SCIENTIST,,…NO any
science magazine will COME forward to PUBLISH my ARTICLE on some basic
principles of science, that “WHY” I ought to share my VIEWs with people with
the HELP OF OUR “SOCIAL” MEDIA that
**“twitter”, “facebook” “blog”**,etc,(Gide Of Our Global Live
Energy->GOOGLE)
THE SUBJECT
WHICH I WISH TO PROVE by “A STORY OF LATEST SCIENTIFIC
DISCOVERY”(ASOLSD)->> “MY NEW FORMULA”
No-1-> eV=Frequency X 0.413334
(electrovolt to frequency)
No-2-> Mass X Charge = Energy (eV)
No-3-> L^2 + Charge ^2 = Mass^2 ( ^
means Square)
No-4-> Primary Color is
FOUR,T1=RED&YEOLLW T2= GREEN&BLUE
No-5-> FREQUENCY CONSTANT OF VISIBLE
LIGHT (1.2919)
No-6-> QUANTUM DIGIT OF
VISISBLE LIGHT (R=3,Org=3.5Yell=4.etc)
No-7-> 4 L= 1.6533 UNIT ,OR MASS OF 1
PROTON (Page-6)->>
No-8->Every wavelength has particles
and charge So that particle’s CHANGE of mass control it’s wavelength
No-9->The timing of creation and the
timing of destruction of the particular particle is CONSTANT
No-10->One molecule will born from
equivalent to 2 electron’s mass,or,energy,or,charge from a neutron
No-11->The changing of an electron’s
energy in a molecular orbit always be in A DEFINITE RULE
No-12-> THE SOURCE OF
Pi (3.14)
No-13-> The different relation of a
molecule or an element with 0.413334
No-14-> The real meaning of “PYTHAGORUS”theory is…
NOW --à-àNo-15-> As my(sree DEBASISH DASGUPTA) calculation
of the Energy of total electrons is ->in every orbit total electron energy not
more than 16.978 unit and less than 16.472754 unit.
When one electron goes up from 1st
to last orbit have no total energy maximum 20.253366 unit.
As per
Bhor’s energy of electron’s –Total energy of every orbit
|
|||||
(-)ev
|
orbit
|
energy
|
charge
|
mass X no
of e
|
Total mass
|
13.6
|
x 1^2
|
=13.6
|
/1.602=
|
8.489x2 =
|
16.978 unit
|
13.6
|
x2^2
|
=3.4
|
/1.602=
|
2.1223x8 =
|
16.978 unit
|
13.6
|
x3^2
|
=1.511
|
/1.602=
|
0.9432x18=
|
16.978
unit
|
Same way
for others orbit= PROVE THAT equal energy in every orbit
|
|||||
[Calculation done by my (sree DEBASISH DASGUPTA) formula no 2
or (ii) Mass x Charge =Energy and electrons energy are taken from picture no -6
(For Example 2nd orbit………) ]
PAGE
No 6
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